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oksano4ka [1.4K]
3 years ago
14

Plz help it’s due very soon

Chemistry
2 answers:
KatRina [158]3 years ago
7 0

Answer:

64

Explanation:

Setler79 [48]3 years ago
5 0

Answer:

192g

Explanation:

so for this find out there moles of CH4 by moles=mass/mr

48/16=3 then use molar ratio 1:2 so times it by 2 which is 6 moles. then uses mass =moles*mr so 6*32=192g is the answer hope this helps to understand.

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Explanation :

As we are given 75 % CO_2 and 25 % N_2 in terms of volume.

First we have to calculate the moles of CO_2 and N_2.

\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole

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\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}

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\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}

\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the CO_2 in the tank in psia is, 32.6 psia.

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