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vivado [14]
3 years ago
13

Find the percent of water in Zn3(PO4)2 x 7H2O

Chemistry
1 answer:
Andreas93 [3]3 years ago
4 0

Answer:

24.66%

Explanation:

To find the percent of water (H2O) in the following compound: Zn3(PO4)2. 7H2O

The atomic mass of the elements are as follows:

Zn = 65g/mol

P = 31g/mol

O = 16g/mol

H = 1g/mol

Hence, molar mass of the compound is as follows:

65(3) + {31 + 16(4)} 2 + 7{1(2) + 16}

195 + 95(2) + 7(18)

195 + 190 + 126

511g/mol

Molar mass of 7H2O

= 7(18)

= 126g/mol

Hence, the percent of H2O in the compound is:

Molar Mass of 7H2O/molar mass of compound × 100

= 126/511 × 100

= 0.2466 × 100

= 24.66%

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2 years ago
Chloroform is a liquid once used for anesthetic. What is the volume of 5.0 g of chloroform? The density of chloroform 1.49 g/mL
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Answer:

3.3557047 mL

Explanation:

The density can be found using the following formula:

d=\frac{m}{v}

Let's rearrange the formula to find the volume, v.

d*v=\frac{m}{v}*v

d*v=m

\frac{d*v}{d} =\frac{m}{d}

v=\frac{m}{d}

The volume can be found by dividing the mass by the density. The mass of the chloroform is 5 grams and the density is 1.49 grams per milliliter. Therefore,

m= 5g \\d= 1.49 g/mL

Substitute the values into the formula.

v=\frac{5g}{1.49 g/mL}

Divide. When we divide, the grams, or g, in the numerator and denominator will cancel out.

v= \frac{5}{1.49}mL

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The volume of 5 grams of chloroform is 3.3557047 milliliters

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In the cathode ray tube experiment, J. J. Thomson passed an electric current through different gases inside a cathode ray tube i
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It showed that atoms can be divided into smaller parts.

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