Using the normal distribution, there is a 0.1894 = 18.94% probability that the sample average will exceed $75.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
The parameters for this problem are given as follows:

The probability that the sample average will exceed $75 is <u>one subtracted by the p-value of Z when X = 75,</u> hence:

By the Central Limit Theorem

Z = (75 - 70)/5.66
Z = 0.88
Z = 0.88 has a p-value of 0.8106.
1 - 0.8106 = 0.1894.
0.1894 = 18.94% probability that the sample average will exceed $75.
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Answer:
114
Step-by-step explanation:
add the areas of all 6 faces
the formula is A= 2(l*w)+2(l*h)+2(h*w)
A=2(8*3)+2(8*3)+2(3*3)=114
answer: 114yd^2
Look up the equation for it
The value of the derivative of functions h'(6) as requested in the task content is; 55.
<h3>What is the value of h'(6)?</h3>
Since it follows from the task content that the function h(x)=4f(x)+5g(x)+1.
Hence, the derivative of h(x) can be evaluated as;
h'(x)=4f'(x)+5g'(x)
On this note, by substitution, it follows that;
h'(6)=4(5)+5(7)
h'(6) = 55.
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Answer: 112
Step-by-step explanation:
Since we were given m and n, we plug them into the expression and solve.
-2(-6)+4(-5)² [exponent]
-2(-6)+4(25) [multiply]
12+100 [add]
112
Now, we know that the value of the expression is 112.