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SashulF [63]
2 years ago
7

If the area of the rectangle is 18 kilometers what are its dimensions?

Mathematics
2 answers:
lapo4ka [179]2 years ago
5 0
The dimensions would be 9 and 2 or 6 and 3
irina [24]2 years ago
4 0
Nine and two or six and three
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Swati is substituting t=5 and t=9 to determine if the two expressions are equivalent.
horrorfan [7]

Answer:

No the two expressions are not equivalent.

Step-by-step explanation:

the given two expressions t=5 and t=9 are not equivalent because t being a variable cant take two numbers at a same time.however if they are placed in given two expressions of 't' such that that they give equal value when the first expression gives a value 'a' at t=5 while the other expression gives a value 'a' at t=9 then those two expressions will be equal.


4 0
2 years ago
Read 2 more answers
The function y=-16t^2 +36 represents the height y (in feet) of a water droplet t seconds after falling from an icicle. After how
NikAS [45]

Answer:

1.5 seconds

Step-by-step explanation:

plug 0 in for y

0=-16t^2+36

then slove for t

-36=-16t^2

-36 / -16 = 9/4

9/4=t^2

square root of 9/4 is 3/2 or 1.5

t=1.5

3 0
1 year ago
Matthew is making a sequence in which -3 is added to each successive term. The 6th term in his sequence is -1. What is the 1st t
Hatshy [7]

Answer:

The first term is 14.

Step-by-step explanation:

The general formula for this kind of sequence (arithmetic) is a(n) = a(1) + (n-1)c, where c is the common difference.  Here, we have a(6) = -1 = a(1) + (6-1)(-3), or -1 +15 = a(1).  The first term is 14.



3 0
2 years ago
Find which term in the geometric sequence 1,3,9,27,... is the first to exceed 7,000.
Zielflug [23.3K]

The common ratio between terms is 3, so the sequence has general n-th term

a_n=3^{n-1}

for n\ge1. The term exceeds 7000 when

3^{n-1}>7000\implies n-1>\log_37000\implies n>1+\log_37000\approx9.06

which means the first time a_n exceeds 7000 occurs when n=10. Indeed,

a_{10}=3^{10-1}=19,683

while the previous term would have been

a_9=3^{9-1}=6561

8 0
3 years ago
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
gladu [14]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

5 0
2 years ago
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