Answer: -640, 2560
each number in the sequence is multiplied by -4 to get the next answer
<span>Highest point = 1406.25
Number of seconds = 9.375
We've been given the quadratic equation y = -16t^2 + 300t which describes a parabola. Since a parabola is a symmetric curve, the highest value will have a t value midway between its roots. So using the quadratic formula with A = -16, B = 300, C = 0. We get the roots of t = 0, and t = 18.75. The midpoint will be (0 + 18.75)/2 = 9.375
So let's calculate the height at t = 9.375.
y = -16t^2 + 300t
y = -16(9.375)^2 + 300(9.375)
y = -16(87.890625) + 300(9.375)
y = -1406.25 + 2812.5
y = 1406.25
So the highest point will be 1406.25 after 9.375 seconds.
Let's verify that. I'll use the value of (9.375 + e) for the time and substitute that into the height equation and see what I get.'
y = -16t^2 + 300t
y = -16(9.375 + e)^2 + 300(9.375 + e)
y = -16(87.890625 + 18.75e + e^2) + 300(9.375 + e)
y = -1406.25 - 300e - 16e^2 + 2812.5 + 300e
y = 1406.25 - 16e^2
Notice that the only term with e is -16e^2. Any non-zero value for e will cause that term to be negative and reduce the total value of the equation. Therefore any time value other than 9.375 will result in a lower height of the cannon ball. So 9.375 is the correct time and 1406.25 is the correct height.</span>
I believe it's 5 to 9 since out of 9 games they win 5 and lose 4. This doesn't account for draws or anything, though.
To find the same value as 3 x 1/10 you first have to solve 3 x 1/10
so how to do this is you have to make 3 into a fraction
so to make 3 into a fraction you can put 3 as the numerator and 1 as the denominator
so you multiply
so 3/10 has the same value as 3x1/10
HOPE THIS HELPS!!!
Hey there!!
Remember : R = range and f ( x ) = y and y = range
R : { 5 , 6 , 7 , 8 }
( 1 ) 5 = 1 x / 2 + 4
... 5 - 4 = x / 2
... 1 = x / 2
... x = 2 = ( 2 , 5 )
( 2 ) 6 = x / 2 + 4
... 2 = x / 2
... x = 4 = ( 4 , 6 )
( 3 ) 7 = x / 2 + 4
... 3 = x / 2
... x = 6 = ( 6 , 7 )
( 4 ) 8 = x /2 + 4
... 4 = x/2
... x = 8 = ( 8 , 8 )
Hope my answer helps!
