There are ----- pairs of the perpendicular line segments shown in the picture of the box .

How do i work out: <br> (y+3) (y-3)<br> ------- = --------- + 2<br> 4 5

Dima020 [189]

Y=13

(when you have fractions like the one in this problem, you get rid of them by multiplying both sides by the denominator.)

4 0

3 years ago

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

2 years ago

Rafeal wants to know if there is a single transformation that will move trapezoid JKLM onto trapezoid PQRS Below

aliina [53]

A. A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R.

Step-by-step explanation:

Since both the trapezoids, trapezoid JKLM and PQRS are congruent, we can do any transformation, may be rotation, reflection and translation.

A 90° counterclockwise rotation of trapezoid JKLM about the origin will move angle L onto angle R is the true statement others are incorrect statements.

When the Preimage is rotated 90° counterclockwise rotation, then its coordinates (x,y) changed into (-y,x)

8 0

3 years ago

2. a. A fish is 12 meters below the surface of the ocean. What is its elevation?

Alex17521 [72]

Answer:

A. -12 meters

B. 28 meters

C. 40 meters

Step-by-step explanation:

The surface of the ocean would be 0.

Taking this into account, 12 meters below would be 0 - 12, which is -12. Therefore A's elevation would be -12.

For the sea bird, 28 meters above the surface, which is again 0, would be 0 + 28. B's elevation is 28.

Since the fish is 12 meters below the surface and the sea bird is 28 meters above the surface, simply add the two numbers up to get a total of 40 meters. C would be 40 meters.

5 0

3 years ago

Read 2 more answers

Please help me, I don't understand this-

Andreas93 [3]

Answer:

i think its J 5,000 pounds

Step-by-step explanation:

5 0

2 years ago