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maria [59]
2 years ago
12

Find the value of the expression 8x^3 if x= -2

Mathematics
2 answers:
notka56 [123]2 years ago
8 0

Answer:

-64

Step-by-step explanation:

8x^3

Let x = -2

8 (-2)^3

8 * -8

-64

Likurg_2 [28]2 years ago
3 0

Answer:

−4096

Step-by-step explanation:

desmos

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neonofarm [45]

Answer:

Use m a t h w a y . c o m

Step-by-step explanation:

It helps with any math homework!! trust me :)

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2 years ago
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A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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7 0
3 years ago
1)The price of a sweater was slashed from #960 to $816 by a shopkeeper in the winter season. Find the rate of discount given by
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Answer:

The discount% is 15%

Step-by-step explanation:

Given : The price of a sweater was slashed from Rs 960 to Rs 816 by a shopkeeper in the winter season.

To find : The rate of discount given by him?

Solution :

According to question,

The market price of the sweater is Rs.960

The selling price of the sweater is Rs.816

The discount on the sweater is given bY

Discount % is given by

Therefore, The discount% is 15%.

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Simplify the expression. - | -13 | =
a_sh-v [17]
Since the -13 has the absolute value signs next to it, the 13 becomes a positive, but there is a negative outside the absolute value, and the negative sign and the absolute value sign cancelled previously, so the expressions is now
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The absolute value signs cancel out a negative only inside the signs, not outside, so the negative sign in the outside keeps.
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