If your asking for what that would be called cause I don't understand what your asking but it would be called the midpoint
f(x) = (x - 4)^2 - 5
Vertex (4 , -5)
This function opens upward and has min. value = -5
So range y >= - 5
So answer is A. -5 <= f(x) < ∞
Answer:
Step-by-step explanation:
Given the points (3, 9) and (9, 1), we must first solve for the slope of the line before proceeding with writing the point-slope form.
In order to solve for the slope (<em>m </em>), use the following formula:
m = (y₂ - y₁)/(x₂ - x₁)
Let (x₁, y₁) = (3, 9)
(x₂, y₂) = (9, 1)
Substitute these values into the given formula:
m = (y₂ - y₁)/(x₂ - x₁)
m = (1 - 9)/(9 - 3)

Therefore, the slope of the line, m = -4/3.
Next, using the slope, m = -4/3, and one of the given points, (x₁, y₁) = (3, 9), substitute these values into the following point-slope form:
y - y₁ = m(x - x₁)
⇒ This is the <u>point-slope form</u>.
Answer: 5-35i
Step-by-step explanation:
I have no explanation. I'm sorry.
Answer:
y= f(x)-5
Step-by-step explanation:
y=f(x) moves 5 to the right