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aev [14]
2 years ago
5

.Martin is an after-school math tutor. He noticed that 6 people still needed help and only Two-fifths of the tutoring session ti

me was left. Since each person is to be given an equal amount of time, Martin wrote the expression below to find the fraction of the tutoring session each person who still needed help would be allotted.
Two-fifths divided by 6

Which expression is equivalent to Martin’s expression?
StartFraction 6 Over 15 EndFraction divided by 6
StartFraction 6 Over 5 EndFraction divided by 2
Five-halves times 6
Two-fifths times 6
Mathematics
1 answer:
Ugo [173]2 years ago
4 0

Answer:

6/15 divided by 6

Step-by-step explanation:

\frac{2}{5} / 6\\= \frac{6}{15} / 6\\

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Help with math please
natulia [17]

Answer: The answer is B

Step-by-step explanation: Because x=6 and y=6 = 12

..y equal twice the times we have right now..... and there is a lot of solutions to equal 12...

4 0
3 years ago
I need it done asapp <br> Will give brainly!!
brilliants [131]

Answer:

Step-by-step explanation:

4(5-2)+(-7)(0.5)

20-8+(-3.5)

12-3.5

8.5

6 0
3 years ago
Read 2 more answers
Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used
ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0
3 years ago
Can someone help me with this please
9966 [12]

Answer:

16

Step-by-step explanation:

94/6 = 15.66667

smallest number of boxes = 16

3 0
2 years ago
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What is BC?<br><br> Enter your answer in the box<br><br> _units
laiz [17]

Answer:

<h2>BC = 25</h2>

Step-by-step explanation:

It's an isosceles triangle (congruent angles ∠C ≅ ∠B).

Therefore AC = AB.

We have the equation:

4x+1=2x+23        <em>subtract 1 from both sides</em>

4x=2x+22       <em>subtract 2x from both sides</em>

2x=22          <em>divide both sides by 2</em>

x=11

Substitute the value of <em>x</em> to the expression BC = 3x - 8:

BC = 3(11) - 8=33-8=25

3 0
3 years ago
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