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aev [14]
2 years ago
5

.Martin is an after-school math tutor. He noticed that 6 people still needed help and only Two-fifths of the tutoring session ti

me was left. Since each person is to be given an equal amount of time, Martin wrote the expression below to find the fraction of the tutoring session each person who still needed help would be allotted.
Two-fifths divided by 6

Which expression is equivalent to Martin’s expression?
StartFraction 6 Over 15 EndFraction divided by 6
StartFraction 6 Over 5 EndFraction divided by 2
Five-halves times 6
Two-fifths times 6
Mathematics
1 answer:
Ugo [173]2 years ago
4 0

Answer:

6/15 divided by 6

Step-by-step explanation:

\frac{2}{5} / 6\\= \frac{6}{15} / 6\\

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If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (StartFraction u Over v EndFraction) (x)? x3 – x2 –x3 +
Len [333]

Answer:

^^look at the picture above it give you the answer^^

Step-by-step explanation

and the answer is C

your welcome hope it helps

7 0
3 years ago
What is (f ° g)(2) and (g ° f)(2) with the set of points f: {(0,4), (1,2), (2,0), (3,2), (4,4)} and g: {(0,4), (1,3), (2,2), (3,
kumpel [21]

Answer:

\large\boxed{(f\circ g)(2)=0}\\\boxed{(g\circ f)(2)=4}

Step-by-step explanation:

f:\{(0,4), (1,2), \underline{(2,0)}, (3,2), (4,4)\}\\\\g:\{\underline{(0,4)}, (1,3), \underline{(2,2)}, (3,1), (4,0)\}\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)\\\\g(2)=2\qquad/from\ (2,2)/\\f\bigg(g(2)\bigg)=f(2)=0\qquad/from\ (2,0)/\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(2)=0\qquad/from\ (2,0)/\\g\bigg(f(2)\bigg)=g(0)=4\qquad/from\ (0,4)/

7 0
3 years ago
A city has a population of 230,000 people. Suppose that each year the population grows by 9%. What will the population be after
zloy xaker [14]

<u>Answer:</u>

<h2><u>385,733</u></h2>

Step-by-step explanation:

If it grows by 9% each year, you can simply do the current population times 109%. Because its an additional 9%.

230,000*109% = 250,700

After the first year, there is a population of 250,700 people.

250,700*109% = 273,263

After the second year, there is a population of 273,263 people.

273,263*109% = 297,856.67

After the third year, there is a population of 297,856.67 people.

297,856.67*109% = 324,663.77

After the fourth year, there is a population of 324,663.77 people.

324,663.77*109% = 353,883.509

After the fifth year, there is a population of 353,883.509 people.

353,883.509*109% = 385,733.025

After the sixth year, there is a population of 385,733.025 people

Round it up to 385,733 people.

7 0
2 years ago
consider the line y=2/3x-0 find the equation of the line that is parallel to this line and passes through the point(8, 4).
Mila [183]
To find the equation take the slope 2/3 y-y(1)=m(x-x(1) y-4=2/3(x-8) = 2/3x-16/3 Next solve for y y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator) y=2/3x-16/3 + 12/3 y=2/3x-4/3
4 0
3 years ago
Write 83 as a sum of tens and ones
MrMuchimi
<span>83 as a sum of 8 tens and 3 ones
.....................................</span>
3 0
3 years ago
Read 2 more answers
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