Answer:
Step-by-step explanation:
Given
y = 3x + 1
Required
Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1
First, the slope of the line has to be calculated;
Th slope of a line is the coefficient of x in its linear equation;
This implies that the slope of y = 3x + 1 is 3
Having calculated the slope of the first line;
The relationship between both lines are perpendicularity; this implies that 
Where m_1 = 3 and m_2 is the slope of the secodnd line
becomes
Divide both sides by 3
The equation of the line can be calculated using the folloing formula
Where 
and
The equation becomes
Cross multiply
Collect like terms
Observation one
From the markings on the diagram <1 = 60o The left triangle is at least isosceles. Therefore equal sides produce equal angles opposite them.
Now we have accounted for 2 angles that are equal (each is 60 degrees) and add up to 120 degrees. The third angle (angle 2) is found from this equation.
<1 + 60 + <2 = 180 degrees. All triangles have 180 degrees.
60 + 60 + <2 = 180
Observation 2
<2 = 60 degrees.
120 + <2 = 180
m<2 = 180 - 120
m<2 = 60 degrees.
Observation 3
m<3 = 120
<2 and <3 are supplementary.
Any 2 angles on the same straight line are supplementary
60 + <3 = 180
<3 = 180 - 60
<3 = 120
Observation 4
m<4 = 40 degrees.
All triangles have 180 degrees. No exceptions.
m<4 + 20 +m<3 = 180
m<4 + 20 + 120 = 180
m<4 + 140 = 180
m<4 = 180 - 140
m<4 = 40
Answer:
52.85
Step-by-step explanation:
perimeter of the rectangle is 40
perimeter of the half circle is 12.85
add those two together and get 52.85
MARK ME BRAINLIEST PLEASE
This depends on the equation.
