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aev [14]
2 years ago
5

.Martin is an after-school math tutor. He noticed that 6 people still needed help and only Two-fifths of the tutoring session ti

me was left. Since each person is to be given an equal amount of time, Martin wrote the expression below to find the fraction of the tutoring session each person who still needed help would be allotted.
Two-fifths divided by 6

Which expression is equivalent to Martin’s expression?
StartFraction 6 Over 15 EndFraction divided by 6
StartFraction 6 Over 5 EndFraction divided by 2
Five-halves times 6
Two-fifths times 6
Mathematics
1 answer:
Ugo [173]2 years ago
4 0

Answer:

6/15 divided by 6

Step-by-step explanation:

\frac{2}{5} / 6\\= \frac{6}{15} / 6\\

You might be interested in
Calculus application
Ugo [173]

Answer:

49m/s

59.07 m/s

Step-by-step explanation:

Given that :

Distance (s) = 178 m

Acceleration due to gravity (a) = g(downward) = 9.8m/s²

Velocity (V) after 5 seconds ;

The initial velocity (u) = 0

Using the relation :

v = u + at

Where ; t = Time = 5 seconds ; a = 9.8m/s²

v = 0 + 9.8(5)

v = 0 + 49

V = 49 m/s

Hence, velocity after 5 seconds = 49m/s

b) How fast is the ball traveling when it hits the ground?

V² = u² + 2as

Where s = height = 178m

V² = 0 + 2(9.8)(178)

V² = 0 + 3488.8

V² = 3488.8

V = √3488.8

V = 59.07 m/s

8 0
3 years ago
Which is the graph of y = ⌊x⌋ – 2?
Alexandra [31]

Answer:

The third graph

Step-by-step explanation:

The Greatest Integer function (also called "floor" function. is in fact the one depicted on your first graph on the left. It indicates the integer part of the real number x.

So, if one translates such function two units down , as requested by the subtraction of 2 of the function y the problem shows, one ends up with the third graph depicted on the page.

5 0
3 years ago
HELP ME PLEASE <br> True or false: z=−5 is a solution to the inequality −2|z−3|&lt;−20.
Dovator [93]

<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>

<em>True or false: z=−5 is a solution to the inequality −2|z−3|<−20.</em>

<em><u>answer:</u></em><em><u> </u></em>

<em>-</em><em>2</em><em>|</em><em>z-3|</em><em><</em><em>-</em><em>2</em><em>0</em>

<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>. </em><em> </em><em> </em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>

<em> </em><em> </em><em> </em><em>-</em><em>2</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>-</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>|</em><em>z-3|</em><em><</em><em>1</em><em>0</em><em> </em>

<em>equation </em><em>1</em><em>:</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>equation </em><em>2</em><em>:</em><em> </em>

<em>z-3<</em><em>1</em><em>0</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>z-3></em><em>-</em><em>1</em><em>0</em><em> </em>

z<13 z>-13

<em>So </em><em>false, </em><em>z=</em><em>-</em><em>5</em><em> </em><em>is </em><em>not </em><em>a </em><em>solution </em><em>to the </em><em>inequality</em><em>.</em>

<em>hope </em><em>this </em><em>helps, </em><em>have </em><em>a </em><em>great </em><em>day! </em><em>:</em><em>)</em>

7 0
2 years ago
If k is parallel to l find the value of a and the value of b.
kipiarov [429]

Answer:

a = 30

b = 40

C

Step-by-step explanation:

This requires that you use a proportion.

a / (a + 15) = 40 / 60

The small triangle's sides are in proportion to the large triangles sides.

Reduce the right. Divide top and bottom by 20

a/(a + 15) = 40/20 // 60/20

a/(a + 15) = 2/3                    

Cross multiply

3a = 2(a + 15)            Remove the brackets on the right.

3a = 2a + 30

Subtract 2a from both sides

3a-2a = 30

a = 30

Find B

b is done exactly the same way.

b/(b+20) = 2/3

3b = 2b + 40

3b - 2b = 40

b = 40

3 0
3 years ago
Matrix L is a 1 ⨯ 8 matrix, matrix M is a 8 ⨯ 8 matrix, matrix N is a 1 ⨯ 1 matrix, and matrix P is a 8 ⨯ 1 matrix. Find the dim
Alenkinab [10]

Answer: fhesfuiewf fjjbeuihr jkfhur

Step-by-step explanation:

7 0
3 years ago
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