When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten
<h3>How to write the number in standard form?</h3>
The number expression is given as:
(2tens 1 one) x 10
2 tens is represented as:
2 * 10
1 one is represented as:
1 * 1
So, the number expression can be rewritten as:
(2tens 1 one) x 10 = (2 * 10 + 1 * 1) x 10
Evaluate the product
(2tens 1 one) x 10 = (20 + 1) x 10
Evaluate the sum
(2tens 1 one) x 10 = (21) x 10
Evaluate the product
(2tens 1 one) x 10 = 210
When the number expression given as (2tens 1 one) x 10 is written in standard form, the standard form is 210 and the unit form is 2 hundred, and 1 ten
Using the above steps as a guide, we have:
- (5 hundreds 5 tens) * 10 ⇒ 5 thousands and 5 hundreds ⇒ 5500
- (2 thousands 7 tens) / 10 ⇒ 2 hundreds and 7 units ⇒ 207
- (4 ten thousands 8 hundred) / 10 ⇒ 4 thousands and 8 tens ⇒ 4080
Read more about standard form at
brainly.com/question/19169731
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The answer is x = 6
hope this helps
I’m hoping you are talking about:
Factor -1/2 out of -1/2x + 6
If so then the answer is
-1/2(x-3)
Hi there! :)
<u>Answer:</u>
In order to maintain the same ratio, she should sell 18 band posters.
<u>Step-by-step explanation:</u>
<u>Initial ratio:</u>
Ratio is: 105 movie posters for 90 band posters = <u>105 : 90</u>
She sells 21 movie posters, which means that we are left with 105 movies minus the 21 she sold.
105 - 21 = 84 → She now has <u>84</u> movie posters.
In order to answer your question, you'll need to use the cross product method:
105 movie posters → 90 band posters
84 movie posters → X
<u>(90 × 84)</u> ÷ 105 = X
<u>7,560 ÷ 105</u> = X
72 = X ⇒ Number of band posters she should have left to maintain the same ratio.
She has 90 band posters :
90 <u>- X</u> = 72
Add "X" to each side of the equation → 72 + X = 72 + X
90 = <u>72</u> + X
Subtract 72 from each side of the equation → 90 - 72 = 18
<u>18 = X</u>
There you go! I really hope this helped, if there's anything just let me know! :)
<span><span>(<span>7y+2<span>y2</span>−7</span>)</span>−<span>(<span>3−4y</span>)</span></span>
<span>=<span>7y</span><span>+4y</span>+2<span>y2</span><span>−7</span><span>−3</span></span>
<span>=11y−2<span>y2</span>−<span>10</span></span>
Hope this helps
