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Trava [24]
3 years ago
13

What’s the answer pleaseeeeeeeee

Mathematics
1 answer:
slega [8]3 years ago
7 0

y^2 +6^2 = 12^2

y^2 +36 = 144

y^2 = 108

sqrt(108) = 10.392 = 6sqrt(3)

 Answer is B 6sqrt(3)

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Which is the graph of f(x) = x2 – 2x + 3?
BaLLatris [955]

Answer:

Step-by-step explanation:

We cannot factor this function out which tells us that there are no zeros. The graph backs this up because we can see that there are none. The easiest way to graph this would start by plugging in points and making a table for yourself.

Lets start by plugging in -1.

(-1)^2-2(-1)+3 =6, this means we have a point at (-1,6).

Now lets plug in 0.

(0)^2-2(0)+3= 3 (0,3)

For plugging in 1

(1)^2-2(1)+3=2 (1,2) (this happens to be the vertex)

And lastly lets plug in 2

(2)^2-2(2)+3=3 (2,3)

Depending on how many points are needed, keep plugging in numbers like we did above.

7 0
3 years ago
Dustin loves to cook with fresh herbs. So, he decides to plant 8 different herbs and keep the small pots on his kitchen windowsi
ololo11 [35]

Answer:

512 ounces

Step-by-step explanation:

there are 16 ounces in a pound so you multiply 4 x 16= 64 ounces for the 4 pounds. Since Dustin had 8 pots you multiply 64 x 8= 512 ounces.

6 0
3 years ago
For which pairs of functions is (fOg)=12x
Komok [63]
G(x) = 3x 
<span>f(x) = 4x

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7 0
3 years ago
Question 7 of 10
klemol [59]
I think the answer is C. 45 units
4 0
2 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
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