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Deffense [45]
3 years ago
10

UHHH HELP OMG WHAT IS THIS I WASNT PAYING ATTENTION SORRY 26 POINTS DO NOT GIVE ME AN ANSWER IF U DONT KNOW HELP i know its easy

but im lost

Mathematics
1 answer:
Karolina [17]3 years ago
3 0

Answer:

m=2/3, b=12

Step-by-step explanation:

When you see an equation in this format, it's called slope-intercept form (y=mx+b, with m being slope and b being y-intercept). So in this case, by looking at our formula, we can tell right away that our slope, or m, is 2/3 and our y-intercept, or b, is 12. HTH :)

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yan [13]

Answer:

<em>0.6 ÷ 0.3 - Option 2.</em>

<em>0.2 × 0.9 - Option 3.</em>

3 0
3 years ago
A student wants to construct the inscribed circle of a triangle. What is the first step he/she should take?
pantera1 [17]

The <em>correct answer</em> is:


d) Construct the angle bisector of each angle in the triangle


Explanation:


The incenter, or center of an inscribed circle, is the point where the angle bisectors of a triangle intersect. This means the first thing we will need to construct is the bisector of each angle of the triangle.

8 0
3 years ago
Read 2 more answers
P and W are twice-differentiable functions with P(7)=2(W(7)). The line y=9+2.5(x-7) is tangent to the graph of P at x=7. The lin
fiasKO [112]

Using the product rule, we have

m(x) = x W(x) \implies m'(x) = xW'(x) + W(x)

so that

m'(7) = 7W'(7) + W(7)

The equation of the tangent line to <em>W(x)</em> at <em>x</em> = 7 has all the information we need to determine <em>m'</em> (7).

When <em>x</em> = 7, the tangent line intersects with the graph of <em>W(x)</em>, and

<em>y</em> = 4.5 + 2 (7 - 7)   ==>   <em>y</em> = 4.5

means that this intersection occurs at the point (7, 4.5), and this in turn means <em>W</em> (7) = 4.5.

The slope of this tangent line is 2, so <em>W'</em> (7) = 2.

Then

m'(7) = 7\cdot2 + 4.5 = \boxed{18.5}

4 0
3 years ago
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Answer: 4,1 read carefully

Step-by-step explanation:

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4 years ago
Figure ABCD is transformed to obtain figure A′B′C′D′:
Kisachek [45]

Step-by-step explanation:

part A:

ABCD is transformed to obtain figure A′B′C′D′:

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A(-4,-4) B(-2,-2) C(-2, 1) D(-4, -1)

2) by translation T (7 0), obtain the image :

A'(3,-4) B'(5,-2) C'(5, 1) D'(3, -1)

part B:

the two figures are congruent.

the figures that transformed by reflection either or translation will obtain the images with the same shape and size (congruent)

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