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3 years ago

5

Please help I don’t know how to set it up

2 answers:

OlgaM077 [116]3 years ago

5 0

Answer:

4a+1s

Step-by-step explanation:

50 divided by 12=4 and a is the variable for albums so 4a

12 x 4 = 48

50-48=$2

Which leaves enough money to buy one song therefore 1s

Hope this helps

Have a great day!

sergij07 [2.7K]3 years ago

4 0

4a+1s is your answer

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fenix001 [56]

Answer: A

Step-by-step explanation: once you line the numbers up in order from least the greatest, the two middle numbers will be 12. Add 12 + 12 and you get 24. Then divide it by 2 and get 12. That is your median. Your 1st quartile will be 10. Your second quartile will be 15. Your minimum number is 4 and your maximum number is 18.

6 0

3 years ago

WILL MAKE BRAINLIEST!!!!!!!<br> PLEASE INCLUDE FULL WORKING!!!!

aleksandrvk [35]

The picture is not opening..

4 0

3 years ago

Los puntos de intersección de los gráficos de f(x)=x2+6x−7 y g(x)=4x−10

alisha [4.7K]

Answer:

Those graphs do not intersect.

Estes gráficos no se intersecciónan

Step-by-step explanation:

The intersection points are x for which:

$f(x) = g(x)$

In this question:

$f(x) = x^{2} + 6x - 7$

$g(x) = 4x - 10$

So

$x^{2} + 6x - 7 = 4x - 10$

$x^{2} + 2x + 3 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$x^{2} + 2x + 3 = 0$

So $a = 1, b = 2, c = 3$

$\bigtriangleup = b^{2} - 4ac = 2^{2} - 4*1*3 = -8$

Sincce $\bigtriangleup$ is negative, there are no solutions, which means that those graphs do not intersect.

7 0

3 years ago

6ibls divided by 10ounces

Norma-Jean [14]

6 ibls = 96 ounces
so <span>6ibls divided by 10ounces =9.6 ibls</span>

8 0

3 years ago

Papessa [141]

$\huge{\fbox{\sf{n=5 }}}$

Step 1:

$⇒ {2}^{n - 5} \times {5}^{n - 4} = 5$

Step 2:

$⇒{2}^{n - 5} \times {5}^{n - 4} = {5}^{1} \times {2}^{0}$

On comparing values we get:

Taking:

${2}^{n - 5} = {2}^{0}$

n-5=0

n=5✓

or

Taking:

${5}^{n - 4} = {5}^{1}$

n-4=1

n=5✓

3 0

3 years ago