9 - x² < 0
<u>-9 -9</u> <u> </u><u /> to remove 9 deduct it from both sides<u></u>
- x² < -9
<u> ÷ -1 ÷-1 </u> to remove the negative sign, divide both sides by -1
x² < 9
<u> √x² < √9</u> to remove the exponent of 2, find the square root of both sides.
x < 3 Choice A.
To check:
9 - x² < 0
9 - 3² < 0
9 - 9 < 0
0 < 0
Answer:
6.5 × 10^-9
Step-by-step explanation:
Answer:
The height of the building is ![73.2\ ft](https://tex.z-dn.net/?f=73.2%5C%20ft)
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle ABC
![tan(38\°)=\frac{BC}{AB}](https://tex.z-dn.net/?f=tan%2838%5C%C2%B0%29%3D%5Cfrac%7BBC%7D%7BAB%7D)
we have
![AB=63\ ft](https://tex.z-dn.net/?f=AB%3D63%5C%20ft)
substitute and solve for BC
![tan(38\°)=\frac{BC}{63}](https://tex.z-dn.net/?f=tan%2838%5C%C2%B0%29%3D%5Cfrac%7BBC%7D%7B63%7D)
![BC=(63)tan(38\°)=49.2\ ft](https://tex.z-dn.net/?f=BC%3D%2863%29tan%2838%5C%C2%B0%29%3D49.2%5C%20ft)
Find the height of the building
The height of the building (h) is equal to
![h=BC+24=49.2+24=73.2\ ft](https://tex.z-dn.net/?f=h%3DBC%2B24%3D49.2%2B24%3D73.2%5C%20ft)