Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
Answer:1/2
Step-by-step explanation:
3/6 =1/2
13 m ...?.........;;;;;;;;;
A midsegment of a triangle is parallel to one side of the triangle, and its length is one half of the length of that side.
If a line is parallel to one side of a triangle and intersects the other two sides, then it divides the sides into segments of proportional lengths.
Answer: the golf ball with hit the ground again after 2.75 seconds
Step-by-step explanation:
The movement of the golf ball from the ground follows the equation h(t)=-16t^2+44t,
where t is the time in seconds, and h(t) is the height of the ball at a given time t
By the time the golf ball hit the ground, the height from the ground would be zero. This means that we would equate the quadratic equation to zero. It becomes
-16t^2+44t = 0
Dividing both sides by t
16t^2/t = 44t/t
16t = 44
t = 44/16
t = 2.75
