The slope of the line is 2/1 and the y-intercept is (0,-3). Using that information, we can figure out two points on the line.
Point 1: (0,-3)
Point 2: (1,-1)
The first one is (v+6)(v-6)
Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
4, there are 4 equal angles
Answer:
11.4
Step-by-step explanation:
So we know that Triangle ACB is similar to Triangle EFD.
This means that their sides are proportional to each other.
We want to find x or side AB. To do so, we can set up a proportion.
The proportional side to AB is ED. Let's also use BC since we know its value. The proportional side to BC is DF. Thus:

Substitute x for AB, 3.8 for Ed, 15 for BC, and 5 for DF. Thus:

Reduce the right:

Cross multiply:

So, the value of x is 11.4
And we're done!