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mojhsa [17]
3 years ago
14

Plz answer this very important​

Mathematics
1 answer:
WARRIOR [948]3 years ago
3 0

Answer:

16

Step-by-step explanation:

From the question given above, the following data were obtained:

1 = 1

2 = 4

3 = 9

4 =?

Observing the data, we can see that the numbers on the right side are simple the squares of the numbers on the left side. This is illustrated below:

1 = 1² = 1

2 = 2² = 4

3 = 3² = 9

Thus, we shall use the same logic to obtain that of 4. This is illustrated below:

4 = 4² = 16

Thus the answer to the question is 16.

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Rewrite the following equation in standard form.<br> y + 4 = 5(x - 8)
Helen [10]

Answer:

5x-y-36=0

Step-by-step explanation:

y+4=5x-40

5x-y=36

4 0
3 years ago
5x−2.5+6x−3= ___ (2x−1)
LiRa [457]

Answer:

5.5

Step-by-step explanation:

So, this is a simple factoring problem. The answer is 5.5(2x-1). So, heres how we get that answer.

So, factoring is basically breaking down the problem into smaller parts. So once we simplify the problem, we can factor it.

Simplify by combining like terms: 5x+6x= 11x and -2.5-3=-5.5

Now we have 11-5.5=?

so, we need to have (2x-1) in our answer because the problem asks for that in the answer.

We need to find a number that satisfies the equation and answer

so, 5.5(2x) is 11x, and 5.5(-1) is 5.5.

5.5 satisfies the equation, therefore is the answer

4 0
4 years ago
Read 2 more answers
What kind of slope is (19,-16)(-7,-15
olasank [31]

Answer:

Slope is -1/26

Step-by-step explanation:

6 0
3 years ago
Which of the following sentences could not be used to represent the equation y/2 = 14?
svetlana [45]
Two divided by a number yields fourteen would be represented by the equation 2/y=14, and that is not right. So, the answer would be the third answer choice
7 0
4 years ago
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What is the equation of the line i slope intercept form of the line passing throughoints (-5, -2)) and (3,-14).
Paraphin [41]

STEP 1

Write out the formula needed

\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \text{Also, m=}\frac{y_{}-y_1}{x_{}-x_1} \end{gathered}

STEP 2

Equate both equations together then substitute the values of the points into the equation.

\begin{gathered} \frac{y_2-y_1}{x_2-x_1}=\frac{y_{}-y_1}{x_{}-x_1} \\ \frac{-14-(-2)}{3-(-5)}=\frac{y-(-2)}{x-(-5)} \\ \frac{-14+2}{3+5}=\frac{y+2}{x+5} \\ -\frac{12}{8}=\frac{y+2}{x+5} \\ -\frac{3}{2}=\frac{y+2}{x+5} \\ \text{Cross multiply} \\ -3(x+5)=2(y+2) \\ -3x-15=2y+4 \\ 2y=-3x-15-4 \\ 2y=-3x-19 \\ \text{Divide both sides by 2} \\ y=-\frac{3x}{2}-\frac{19}{2} \end{gathered}

5 0
1 year ago
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