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mojhsa [17]
2 years ago
14

Plz answer this very important​

Mathematics
1 answer:
WARRIOR [948]2 years ago
3 0

Answer:

16

Step-by-step explanation:

From the question given above, the following data were obtained:

1 = 1

2 = 4

3 = 9

4 =?

Observing the data, we can see that the numbers on the right side are simple the squares of the numbers on the left side. This is illustrated below:

1 = 1² = 1

2 = 2² = 4

3 = 3² = 9

Thus, we shall use the same logic to obtain that of 4. This is illustrated below:

4 = 4² = 16

Thus the answer to the question is 16.

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Scientific notation 20,000+3,400,000= an example to would be helpful
Viefleur [7K]
20 000 is as much as 20 * 1 000, so we can write it as: 20 * 10^3
3 400 000 is as much as 34 * 100 000, so we can write it as: 34 * 10^5

The sum in scientific notation would look like this:

20 * 10^3 + 34 * 10^5

I hope that's what you meant :)
4 0
3 years ago
Read 2 more answers
A cylindrical tank is filled with 66.85 mm3 of fuel. The area of the base of the cylinder is 15 mm2. What is the height of the f
Rashid [163]
Volume = (Area of the base)x(Height)
66.85 = 15(H)
66.85/15 = H
H = 4.4567

The height is 4.4567mm.
3 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Find the difference (−2g+7)−(g+11)
RUDIKE [14]

Answer:

-3g -4

Step-by-step explanation:

plz brainestt

6 0
3 years ago
Read 2 more answers
If 20 articles cost ? 90, then the cost of 9 articles is ?<br> ? 45<br> ? 4.50<br> ? 40.50<br> ? 42
lapo4ka [179]

Answer:

40.50 is correct answer according to me

5 0
3 years ago
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