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3 years ago

The problem it takes one week for a crew of workers to have 3/ 5 km of a road at that rate is how long will it take to pave 1 km

Mathematics

1 answer:

nikdorinn [45]3 years ago

4 0

It will take them 2 weeks

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-18x-17=-53

nydimaria [60]

-18x-17=-53 /add 17 to both sides

-18x-17+17=-53+17

-18x=-36

x=(-36)/(-18)

x=2

5 0

3 years ago

A local television station runs 2.5 minutes of commercials during every 30 minutes of programming. At this rate, how many minute

umka21 [38]

Answer:

12.5 minutes of commercials

Step-by-step explanation:

9:30 - 7:00 = 2 and a half hours on air = 150 minutes.

150 / 30 = 5

5 x 2.5 = 12.5

8 0

3 years ago

Read 2 more answers

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

3 years ago

Marla received a $15 tip on a meal that cost $75.

stealth61 [152]

75x0.20=15 answer is 20%

3 0

3 years ago

A toy train has 8 compartments and an engine that is 8 inches long. Each compartment is 4 inches long. Each compartment is joine

luda_lava [24]

Answer:

64in

Step-by-step explanation:

links=8*3=24

compartments + engine=4*8+8=40

40+24=64

3 0

3 years ago