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sashaice [31]
2 years ago
6

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

and from (6, 1) to (7, 0)
Mathematics
1 answer:
Dima020 [189]2 years ago
6 0

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

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You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.
RUDIKE [14]
Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

xy = 288  \\  \\  \\  \\ \Rightarrow y= \frac{288}{x}

Substituting for y into the equation for the length of fencing needed, we have

P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}

For the amount of fencing to be minimum, then

\frac{dP}{dx} =0 \\  \\ \Rightarrow1- \frac{576}{x^2} =0 \\  \\ \Rightarrow \frac{576}{x^2} =1 \\  \\ \Rightarrow x^2=576 \\  \\ \Rightarrow x=\sqrt{576}=24

Now, recall that

y= \frac{288}{x} = \frac{288}{24} =12

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.
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3 years ago
Simplify negative 5 minus the square root of negative 44 negative 5 minus 4 times the square root of 11 i negative 5 minus 4 i t
Anika [276]

Answer:

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Step-by-step explanation:

We want to simplify:

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We rewrite the expression under the radical sign to obtain:

-5-\sqrt{4\times11\times -1}

We split the expression under the radical sign to get:

-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}

Recall that:

\sqrt{-1}=i

This implies that:

-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}=-5-2\sqrt{11}i

Therefore -5-\sqrt{-44}=-5-2\sqrt{11}i

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pav-90 [236]

Answer: g = 10

Step-by-step explanation: 8g + 3 = –6g + 13g + 13

                                             8g + 3 = (–6g + 13g) + (13)

                                             8g + 3 = 7g + 13

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