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lawyer [7]
3 years ago
14

(-14)-8solución a esta cuenta ​

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Step-by-step explanation:

Answers 112..................

.......

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20% and $20,000

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Simplify<br> 50(x^2+7x+6)
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50\cdotx^2+50\cdot7x+50\cdot6

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3 years ago
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According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a) compute the mean and standard
larisa [96]
The given problem describes a binomial distribution with p = 60% = 0.6. Given that there are 400 trials, i.e. n = 400.

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\mu=np=400\times0.6=240

The standard deviation is given by:

\sigma=\sqrt{npq} \\  \\ =\sqrt{np(1-p)} \\  \\ =\sqrt{400(0.6)(0.4)} \\  \\ =\sqrt{96}=9.80


b.)  The mean means that in an experiment of 400 adult smokers, we expect on the average to get about 240 smokers who started smoking before turning 18 years.


c.) It would be unusual to observe <span>340 smokers who started smoking before turning 18 years old in a random sample of 400 adult​ smokers because 340 is far greater than the mean of the distribution.
340 is greater than 3 standard deviations from the mean of the distribution.</span>
5 0
2 years ago
PLZ HELP!!!! Choose all that are correct A: Random samples from the same population will vary from sample to sample.
kirill [66]

Answer:a,d

Step-by-step explanation:

5 0
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