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Flauer [41]
3 years ago
6

Which of the following terms best describes three points that all lie in a

Mathematics
2 answers:
Lena [83]3 years ago
8 0

Answer:

A.

Explanation:

Collinear

mart [117]3 years ago
6 0
Answer: A- Collinear
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that confusing

Step-by-step explanation:

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What is the quotient to 5.4 and 11.88
adell [148]
2.2. Divide 11.88 by 5.4
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Find the equation of the line passing through the points (-2/3,1) and (-2,1/2). Write the equation in standard form.
7nadin3 [17]
Standard form is y = mx + b.
To find the slope, m, we must find the 'rise over run,' or the difference in y divided by the difference in x. We do this by:
\frac{y1 - y2}{x1 - x2}  =  \frac{ (-  \frac{2}{3} ) - ( -2 )}{(1) - ( \frac{1}{2} ) } =  \frac{ \frac{4}{3} }{ \frac{1}{2} } \\  =  \frac{4}{3}  \times  \frac{2}{1}  =  \frac{8}{3}
Therefore, the slope is 8/3.

To find b, we must plug in the slope and one point:
(1) = ( \frac{8}{3} )( -  \frac{2}{3} ) + b \\ 1 =  -  \frac{16}{9}  + b \\  \frac{25}{9}  = b
Therefore, b is 25/9, and the total equation is
y =  \frac{8}{3} x +  \frac{25}{9}
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3 years ago
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valentinak56 [21]
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4 years ago
A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

3 0
3 years ago
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