Answer:
C. k=68, t=52
Step-by-step explanation:
Let u, v, y represent the measures of the unmarked angles at the respective vertices. The angles of the equiangular triangle are all 180°/3 = 60°, so we have the relations ...
- y=v
- y+v+k = 180
- v+64+60 = 180
- u=64
- u+64+t = 180
From these relations, we know that
... v = 180 -124 = 56 . . . . . 3rd equation above
... 56 +56 +k = 180 . . . . . . 2nd equation above, with y=v=56
... k = 180 -112 = 68 . . . . . above with 112 subtracted
... t = 180 -128 = 52 . . . . . 5th equation above with u=64 and 128 subtracted
16.454 is greater than 16.45.
Answer:
(3x +2)(x +1)
Step-by-step explanation:
A number of different ways are suggested for doing this. One that seems straightforward is this.
For ax^2 +bx +c, look for factors of ac that total b. Here we have ...
ac = 3·2 = 6
b = 5
It is easy to see that the factors we just multiplied to get 6 are ones that total 5: 3+2 = 5.
Now, rewrite the "bx" term using this sum.
3x^2 +3x +2x +2
Factor each pair of terms.
3x(x +1) +2(x +1)
And factor out the common factor:
(3x +2)(x +1)
Answer:
Ten thousandths
Step-by-step explanation:
The 4 is in the ones place, so the 5 is in the tenths, the 0 in the hundredths, the 1 in the thousandths, so the 2 is in the ten thousandths.
Answer:
25% .
Step-by-step explanation:
