Let his total money be x.
He spent (3/7)*x of his money.
He gave 1/4(x-3/7x) to his sister.
which is : (1/4)*(4/7)*x = (1/7)*x
Now,
How much money he have in the beginning =
(3/7)*x+(1/7)*x+120=x
(4/7)*x+120=x
120=x-(4/7)*x
120=(3/7)*x
x=120*7/3 [cross multiplication]
x=280.
So, Alex had $280 in the beginning.
Answer:
$4706.81
Step-by-step explanation:
The value each year is multiplied by 100% -12% = 88% = 0.88. After 13 years, the value is 0.88^13 ≈ 0.1897906 times what it was originally: ≈ 4,706.81 dollars.
Answer:
Option 3 or Option 4.
Step-by-step explanation:
I have this doubt because actually, a rhombus with a right angle (one) is not necessarily a square. Some rhombuses have one right angle and are still not squares. Now, if the four angles are right, it is a square, but this only says one.
On other hand, a parallelogram with congruent diagonals isn't a square necessarily either. Rectangles have congruent diagonals and are parallelograms.
In case you only can answer with one, I'll say is option 3, hope it helps!
Answer:
the answer is B
Step-by-step explanation:
Step-by-step explanation:
Using the point C (-4,-2) and the refection rule:
