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3 years ago

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Mathematics

1 answer:

Rus_ich [418]3 years ago

8 0

Answer:

225 minutes

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Please help me with the following (1-5)

Ivanshal [37]

$1. \: 405352 \: cm = 4.05352 \times {10}^{5} \: cm$

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2. 7.6352 x 10-3 kg ( This is scientific notation) [ If you want —> Standard notation]

7.6352 x 10^ -3 kg = 0.0076352 kg

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$3. \: \: 3.1 \times 10 ^{4} mm + 4.87 \times {10}^{5} \: mm \\ 0.31\times 10 ^{4} mm + 4.87 \times {10}^{5} \: mm \\ = 5.18 \times {10}^{5} \: mm$

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$4. \: \: (4.8 \times {10}^{5} \: km) \times (2.0 \times {10}^{3} \: km ) \\ = 9.6 \times {10}^{8} \: km$

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$5.(3.3 \times{10}^{ - 4}\: ml)\div(1.1 \times {10}^{ - 6}\: ml) \\ \\ \frac{3.3 \times {10}^{ - 4} \: ml}{1.1 \times {10}^{ - 6} \: ml} = \frac{33 \times {10}^{ - 4} \: ml}{11 \times {10}^{ - 6} \: ml} \\ \\ = \frac{33 \times {10}^{ - 4 + 6} }{11} ml \\ \\ = 3 \times {10}^{2} \: ml$

I hope I helped you^_^

6 0

3 years ago

the shopkeeper received an interest of $6159 from an investment that offers compound interest at 3.5% p.a. after 10 years. What

Sati [7]

Answer:

Amount invested = $15,000 (Approx.)

Step-by-step explanation:

Given:

Amount of interest received = $6,159

Rate of interest = 3.5%

Number of year = 10 year

Find;

Amount invested

Computation:

Using compound interest formula

I = P[(1+r)ⁿ - 1]

6,159 = Amount invested[(1+3.5%)¹⁰ - 1]

6,159 = Amount invested[(1+0.035)¹⁰ - 1]

6,159 = Amount invested[(1.035)¹⁰ - 1]

Amount invested = $15,000 (Approx.)

8 0

3 years ago

The difference between twice the product of a and b and the quotient of these

VladimirAG [237]

Answer:

DIFFERENCE – The difference of two numbers is the result of subtracting these two numbers. PRODUCT – The product of two or more numbers is the result of multiplying these numbers. QUOTIENT – The quotient of two numbers is the result of the division of these numbers.

Step-by-step explanation:

8 0

3 years ago

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Simplify completely:<br> 3<br> 4i

drek231 [11]

3/4 is already simplified<span> completely.</span>

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3 years ago

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A car company says a car will get 25 miles per gallon on the highway with a 15% error margin.

fenix001 [56]