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3 years ago

Find the slope of the lines graphed below. Giving brainliest to whoever answers all correct.

Mathematics

2 answers:

Rashid [163]3 years ago

5 0

Answer:

1.slope is 2

2.slope is -3/5

3.slope is 1

4.vertical line slope 0 undefined

5.x=-5

6.horizontal line slope 0 undefined

Step-by-step explanation:

Brrunno [24]3 years ago

4 0

Answer:

1) 2 2) -3/5 3) 1 4) Undefined 5) -5 6) 0

Step-by-step explanation:

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can you simplify 183/100 to fraction (it is improper fraction and i need to know if it can be simplified or not)

NikAS [45]

You can turn it into a mixed number 1 83
--
100

7 0

4 years ago

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The formula for the bowline of a sphere is V=4/3πr^3. solve for r

Tpy6a [65]

Answer:

$r=\sqrt[3]{\frac{3V}{4\pi}}$

Step-by-step explanation:

$v= \frac{4}{3} \pi r^3$

We need to isolate 'r'

To isolate 'r' , first multiply by 3 on both sides

$3v=4* \pi r^3$

divide by 4pi on both sides

$\frac{3V}{4\pi} = r^3$

Take cube root on both sides

$\sqrt[3]{\frac{3V}{4\pi}}= r$

5 0

3 years ago

15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 +5% sales tax what was the t

Artist 52 [7]

Answer:

$478.80

Step-by-step explanation:

We have been given that 15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 plus 5% sales tax.

First of all, we will find cost of each meal with tax as:

$\text{Cost of each meal with tax}=\$12+\$12\times \frac{5}{100}$

$\text{Cost of each meal with tax}=\$12+\$12\times 0.05$

$\text{Cost of each meal with tax}=\$12+\$0.6$

$\text{Cost of each meal with tax}=\$12.6$

Now, we will find total persons at the sport banquet as:

$\text{Total persons at banquet}=15+2+21$

$\text{Total persons at banquet}=38$

To find the total cost of food for the banquet, we will multiply cost of food for each person by 38.

$\text{Total cost of food for the banquet}=\$12.6\times 38$

$\text{Total cost of food for the banquet}=\$478.8$

Therefore, the total cost of food for the banquet is $478.80.

5 0

3 years ago

Write the standard form equation of the ellipse shown in the graph, and identify the foci.

vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3) and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

$\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1$

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6 and b = 4

The standard equation becomes

$\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1$

$\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1$

Foci are (h,k+c) and (h,k-c)

$c=\sqrt{a^2-b^2}$

Plug in the a=6 and b=4

$c=\sqrt{6^2-4^2}$

$c=\sqrt{20}$

$c=2\sqrt{5}$ , we know h=-2 and k=-3

Foci are $(-2,-3+2\sqrt{5})$ and $(-2,-3-2\sqrt{5})$

Option A is correct

6 0

4 years ago

14. 7 + y ( 2y + 6) - 2y?

marusya05 [52]

Answer:

2y²-2y.?+6y+98 esas es la respuesta . espero que te halla servido.

4 0

3 years ago

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