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3 years ago

6

Each of 8 cats in a pet store was weighted here are their weights 16 13 11 11 8 13 9 9 find the median and mean

1 answer:

Liula [17]3 years ago

6 0

Answer:

16 13 13 11 11 9 9 8 Median = 11 Mean = 11.25

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Find the missing lengths of the sides

Ket [755]

ANSWER

The correct answer is C

EXPLANATION

The given triangle is a right triangle. Since two angles are equal, it is a right isosceles triangle.

This implies that, x=8 units.

Using Pythagoras Theorem,

${y}^{2} = {8}^{2} + {8}^{2}$

This implies that:

${y}^{2} = 64 + 64$

${y}^{2} =128$

Take positive square root,

${y} = \sqrt{128}$

${y} = 8 \sqrt{2}$

The correct answer is C

5 0

3 years ago

Read 2 more answers

Anna is x years old and her sister is 5 years older. How old was her sister 5 years ago?

777dan777 [17]

Answer:

$x$

Step-by-step explanation:

$x + 5 - 5 = x$

8 0

3 years ago

Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP

erik [133]

Answer:

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

Step-by-step explanation:

we have

$y=-x^{2} +2x+10$ ----> equation A

$y=x+2$ ----> equation B

Solve the system by substitution

substitute equation B in equation A

$x+2=-x^{2} +2x+10$

solve for x

$-x^{2} +2x+10-x-2=0$

$-x^{2} +x+8=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2} +x+8=0$

so

$a=-1\\b=1\\c=8$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}$

$x=\frac{-1\pm\sqrt{33}} {-2}$

$x=\frac{-1+\sqrt{33}} {-2}$ -----> $x=\frac{1-\sqrt{33}} {2}$

$x=\frac{-1-\sqrt{33}} {-2}$ -----> $x=\frac{1+\sqrt{33}} {2}$

<em>Find the values of y</em>

For $x=\frac{1-\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1-\sqrt{33}} {2}+2$ ----> $y=\frac{5-\sqrt{33}} {2}$

For $x=\frac{1+\sqrt{33}} {2}$

$y=x+2$

$y=\frac{1+\sqrt{33}} {2}+2$ ----> $y=\frac{5+\sqrt{33}} {2}$

therefore

The solutions of the system of equations are the points

$(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})$

$(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})$

5 0

3 years ago

What is the value of y?

Nataliya [291]

Answer:

B. 85

Step-by-step explanation:

I haven't taken Geometry in 2 years So I don't remember how to explain it.

5 0

3 years ago

Mitch needs four 10 gram samples of NaCl (Sodium Chloride) for an experiment. Mitch is using a balance that measures to 1/10 of

trapecia [35]

<span>the complete question in the attached figure
</span>
The answer is the option A 9.9 grams
because the balance is accurate to the nearest 1/10 gram; thus, the <span>highest level of accuracy appropriate to the limitations of the balance is 0.10 gram (1/10)</span>

6 0

3 years ago