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Leviafan [203]
3 years ago
13

A 4 meter long ladder leans against a 90 degree wall at a 68 degree angle.

Mathematics
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

Step-by-step explanation:

We use trig to answer these questions:

sin x = opposite side of a triangle / hypotenuse

cos x = adjacent side / hypotenuse

Construct a right triangle with hypotenuse 4 m and lower angle 68 degrees.

The height of the top of the ladder  is then defined by:

sin 68 degrees = height / 4 m, which yields (4 m)(sin 68) = height =

3.71 m

and the distance of the bottom of the ladder from the wall as follows:

cos 68 degrees = horizontal distance / hypotenuse =

1.50 m

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Question 1(Multiple Choice Worth 2 points)
dusya [7]

Answer:

6x +47

Step-by-step explanation:

f(x) = 6x + 11

g(x) = x + 6

now f[g(x)]=<em>by</em><em> </em><em>substituting</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>g</em><em> </em><em>(</em><em>x</em><em>)</em>

<em>to</em><em> </em><em>f</em><em> </em><em>(</em><em>x</em><em>)</em>

<em>f[g(x)]</em><em>=</em><em>6</em><em> </em><em>(</em><em>x</em><em>+</em><em>6</em><em>)</em><em>+</em><em>11</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>6x</em><em>+</em><em>36</em><em>+</em><em>11</em>

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7 0
4 years ago
Help please asap!!!!
Amanda [17]
Since 90 degrees is 1/4 of a circle then 1/4 of 12 is 12/4 = 3m^2
8 0
3 years ago
What is −15÷3/5? −25 −9 −19 −125
Yakvenalex [24]

Answer: -25

Step-by-step explanation:

Hoped this works :3

8 0
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Read 2 more answers
Vasudevan invested rupees 60000 at an interest rate of 12% per annum compounded half yearly what amount would he get after 1 yea
Ganezh [65]

Answer:

Given that, Vasudevan invested ₹ 60,000

For Compound Interest (C.I.)

A = P[1 + (r/100)]n

P = ₹ 60,000

n = 6 months and 1 year

R = 12% p.a. compounded half-yearly

where , A = Amount, P = Principal, n = Time period and R = Rate percent

(i) For easy calculation of compound interest, we will put Interest Rate as 6% half-yearly and n = 1.

Compound Interest to be paid for 6 months

A = P[1 + (r/100)]n

A = 60000[1 + (6/100)]1

A = 60000[(100/100) + (6/100)]

A = 60000 × (106/100)

A = 60000 × 1.06

A = ₹ 63600

(ii) Compound Interest to be paid for 12 months (1 year) compounded half yearly.

So, assume n = 2, r = 6%

A = P[1 + (r/100)]n

A = 60000[1 + (6/100)]2

A = 60000[(100/100) + (6/100)]2

A = 60000 × (106/100) × (106/100)

A = 60000 × (11236/10000)

A = 60000 × 1.1236

A = ₹ 67416

4 0
3 years ago
What is the answer to this problem
Lelu [443]

(x - 5) [times] 2 = 11


3 0
3 years ago
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