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sweet-ann [11.9K]
3 years ago
6

LaToya has $113.94 in her checking account. During the week she goes to an ATM and withdraws $40. She is charged a usage fee of

$2.50. The following week she deposits her paycheck of $189.73. She writes two checks, one for $22.50 and the other for $70.18. What is the current balance in her checking account?
Mathematics
2 answers:
Scilla [17]3 years ago
8 0
113.94-42.50+189.73-22.50-70.18= $168.49

LaToya has $168.49 in her checking account
olasank [31]3 years ago
6 0
Hey You! 

Step 1: 

113.94 - 40 = 73.94

Step 2: 

73.94 - 2.50 = 71.44

Step 3: 

71.44 + 189.73 = 261.17

Step 4: 

261.17 - 22.50 = 238.67

Step 5: 

238.67 - 70.18 = 168.49

Latoya has a current balance of $168.49 in her checking account. 
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Answer:

a.\  \mu_p=750\ \ , \sigma_p=0.005\\\\b.\  \mu_p=150\ \ , \sigma_p=0.0113\\\\c.\  \mu_p=75\ \ , \sigma_p=0.0160

Step-by-step explanation:

a. Given p=0.15.

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\mu_p=np\\\\=0.15\times 5000\\\\=750

-The standard deviation is calculated using the formula:

\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\=\sqrt{\frac{0.15(1-0.15)}{5000}}\\\\=0.0050

Hence, the sample mean is μ=750 and standard deviation is σ=0.0050

b. Given that p=0.15 and n=1000

#The mean of a sampling proportion  of n=1000 is calculated as:

\mu_p=np\\\\=1000\times 0.15\\\\\\=150

#-The standard deviation is calculated as follows:

\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.15\times 0.85}{1000}}\\\\\\=0.0113

Hence, the sample mean is μ=150 and standard deviation is σ=0.0113

c. For p=0.15 and n=500

#The mean is calculated as follows:

\mu_p=np\\\\\\=0.15\times 500\\\\=75

#The standard deviation of the sample proportion is calculated as:

\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.15\times 0.85}{500}}\\\\\\=0.0160

Hence, the sample mean is μ=75 and standard deviation is σ=0.0160

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Add $3.85 and $2.09 to get $5.94

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Answer:

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Step-by-step explanation:

Find 25% of 30 and then take away that amount from 30.

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