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Orlov [11]
3 years ago
10

The adult weighs 84.09 kg. Calculate the adult’s weight in kilograms to pounds . Show work

Mathematics
1 answer:
pogonyaev3 years ago
4 0

The adult weight in pounds is 185.39 lb

<u>Solution:</u>

Given that adult weighs 84.09 kilogram

To find : Adult’s weight in kilograms to pounds

We have the change the weight of the adult from kilogram to pound

The conversion between kilogram and pound is as follows:-

1 kilogram = 2.204623 lb

To find the adult weight in pound, we need to multiply the adult weight in kilogram by 2.204623

<em><u>Converting 84.09 kg to pound:</u></em>

\begin{array}{l}{84.09 \mathrm{kg}=84.09 \times 1 \mathrm{kg}} \\\\ {84.09 .09 \times 2.204623=185.39 \mathrm{lb}}\end{array}

Therefore the weight of the person in pound = 185.39 lb

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Ravi sold 1/5 of his apples. He gave his friend 2/5 of the remainder. Ravi remained with 60. How many apples did ravi have at fi
zheka24 [161]

Answer:

The number of Apples did Ravi have at first is 125 .

Step-by-step explanation:

Let the number of Apples did Ravi have at first = x

The Apples which is sold by Ravi = \frac{1}{5} of x

So, remainder now = x - \frac{1}{5} of x = \frac{4}{5} of x

The apples given to his friend = \frac{2}{5} of \frac{4}{5} x

I.e The apples given to his friend =  \frac{8}{25} of x

Now, The remaining Apples did Ravi have = 50

∴ According to question

\frac{4}{5} of x -  \frac{8}{25} of x = 60

Or,  \frac{20-8}{25} of x = 60

Or,  \frac{12}{25} of x = 60

∴ x = \frac{25\times 60}{12} = 125

Hence The number of Apples did Ravi have at first is 125 .  Answer

8 0
3 years ago
The double number line shows the price of 1 cupcake.
mr Goodwill [35]
5 cupcakes = $7.5
18 cupcakes = $27
4 0
3 years ago
The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that
wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \lambda e^{-\lambda x}

In which \lambda is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\lambda x}

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

In all 3 cases, we want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = 1 - e^{-5\lambda}

(a) lambda=.5

P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821

(b) lambda=0.9

P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111

(c) lambda=1.1

P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041

7 0
4 years ago
Does anyone know this need help
madreJ [45]

Answer:

32 m

Step-by-step explanation:

The distance across the river is give as x and we are interested in finding the value of x.

Both the triangles are similar by AA Postulate.

Therefore,

20/x = 10/16 (by c.s.s.t.)

2/x = 1/16

x = 16*2

x = 32 m

8 0
3 years ago
What is the product 1/5 x 2 ?
lukranit [14]
That would be 1

I hope I've helped!
3 0
3 years ago
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