The system of equation to be graphed is the following :
![f(x)=\log_{0.5}x\\f(x)=\log_{3}(2+x)](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog_%7B0.5%7Dx%5C%5Cf%28x%29%3D%5Clog_%7B3%7D%282%2Bx%29)
And the solution is the intersection point of the two graphs .
Answer:
<u>x= -7 , y= 9</u>
Steps:
4x+3y=-1
5x+4y=1
First, multiply the top equations by -5, and the bottom by 4 to get :
-20x-15y=5
20x+16y=4
Then, you’re going to add the two equations with them being on top of each other so you can easily see what cancels out :
-20x-15y=5
+ 20x+16y=4
———————
0+1y=9
From this, you get :
y=9
Now that you have one variable, find x by substituting 9 for y in one of the equations, I choose :
4x+3y=-1
So :
4x+3(9)=-1
Then simplify by multiplying 3 and 9 :
4x+27=-1
Then subtract 27 on each side :
4x=-28
Then, divide by 4 to get that :
x= -7
Hope this helps!!
Answer:
-5,-1
Step-by-step explanation:
add 4 to get the next number
28 men are needed to paint the room in 3 hours
<h3><u>Solution:</u></h3>
Given that it takes 12 hours for 7 men to paint a room
We are asked to find number of men required to paint the room in 3 hours
Recognize, "paint the room" is 1 task. One job.
7 men -------- 12 hours ------ 1 job
(7/7) = 1 men ------- 12 x 7 (84) ------- same 1 job
The one men is rate is 84 hours to do the job
We can express this as 1/84 jobs per hour, the one-person rate
Now lets find how many men needed to paint the room in 3 hours
Let the required number of men for 3 hours be "a"
The rates of each person is simply additive.
![a \times \frac{1}{84} \times 3 = 1](https://tex.z-dn.net/?f=a%20%5Ctimes%20%5Cfrac%7B1%7D%7B84%7D%20%5Ctimes%203%20%3D%201)
corresponds to rate x hours = jobs and "a" is a variable for how many men
![a \times \frac{1}{28} = 28](https://tex.z-dn.net/?f=a%20%5Ctimes%20%5Cfrac%7B1%7D%7B28%7D%20%3D%2028)
Thus 28 men are needed to paint the room in 3 hours