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3 years ago

What is it called when your equation is 0x=5

Mathematics

1 answer:

laila [671]3 years ago

8 0

I just write not possible

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2 years ago

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M(12, 1) is the midpoint of DG. If D is at (6, 5), then where is G?

sukhopar [10]

Answer:

18, -3

using the formula for midpoint M=(x1+x2)/2 ,(y1+y2)/2

4 0

3 years ago

Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Wr

deff fn [24]

Answer:

727.29 − 248.50 + x ≥ 500 727.29 − 248.50 − x ≤ 500. Hope this helps!

Step-by-step explanation:

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3 years ago

What reason justifies the statement that mDAB is 100

Varvara68 [4.7K]

Need more info...........

3 0

3 years ago

The largest set of x values satisfying

velikii [3]

Answer:

If $p\ge -\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

Step-by-step explanation:

Solve two inequalities for x.

1. $2,018x-p$

Separate terms with x and without x into two sides:

$2,018x-2,020x$

Multiply by -1:

$2x>-2p\\ \\x>-p$

2. $7x+3p$

Separate terms with x and without x into two sides:

$7x-10x$

Multiply by -1:

$3x>2+3p\\ \\x>\dfrac{2}{3}+p$

Find the largest set of x values satisfying both inequalities:

$x>-p\\ \\x>\dfrac{2}{3}+p$

$-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p$

then $x>-p$ and $mn=-p=p\cdot (-1),\ m+n=p-1.$ In this case both m and n are negative.

If $p>-\dfrac{1}{3},$ then $x>\dfrac{2}{3}+p$ and $mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p$

If $p=-\dfrac{1}{3},$ then $x>\dfrac{1}{3}$ and $mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}$

7 0

3 years ago