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Mrrafil [7]
3 years ago
9

What is it called when your equation is 0x=5

Mathematics
1 answer:
laila [671]3 years ago
8 0
I just write not possible
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PLEASE HELP. I NEED THIS ASAP.
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6 0
2 years ago
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M(12, 1) is the midpoint of DG. If D is at (6, 5), then where is G?
sukhopar [10]

Answer:

18, -3

using the formula for midpoint M=(x1+x2)/2 ,(y1+y2)/2

4 0
3 years ago
Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Wr
deff fn [24]

Answer:

727.29 − 248.50 + x ≥ 500 727.29 − 248.50 − x ≤ 500. Hope this helps!

Step-by-step explanation:

5 0
2 years ago
What reason justifies the statement that mDAB is 100
Varvara68 [4.7K]
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3 0
3 years ago
The largest set of x values satisfying
velikii [3]

Answer:

If p\ge -\dfrac{1}{3}, then x>\dfrac{2}{3}+p and mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p

Step-by-step explanation:

Solve two inequalities for x.

1. 2,018x-p

Separate terms with x and without x into two sides:

2,018x-2,020x

Multiply by -1:

2x>-2p\\ \\x>-p

2. 7x+3p

Separate terms with x and without x into two sides:

7x-10x

Multiply by -1:

3x>2+3p\\ \\x>\dfrac{2}{3}+p

Find the largest set of x values satisfying both inequalities:

x>-p\\ \\x>\dfrac{2}{3}+p

If

-p>\dfrac{2}{3}+p\\ \\-2p>\dfrac{2}{3}\\ \\2p

then x>-p and mn=-p=p\cdot (-1),\ m+n=p-1. In this case both m and n are negative.

If p>-\dfrac{1}{3}, then x>\dfrac{2}{3}+p and mn=\dfrac{2}{3}+p=\left(\dfrac{2}{3}+p\right)\cdot 1,\ \ m+n=\dfrac{5}{3}+p

If p=-\dfrac{1}{3}, then x>\dfrac{1}{3} and mn=\dfrac{1}{3}=\dfrac{1}{3}\cdot 1,\ \ m+n=\dfrac{4}{3}

7 0
3 years ago
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