X = 4 and Y = 9. I did a complicated way of doing it so if u copy it it would look weird
Answer:
0.9 , 0.088 , 0.032
Step-by-step explanation:
0.9 --> 1st greatest
0.088 --> 2nd greatest
0.032 --> 3rd greatest
So, 0.9 , 0.088 , 0.032
Answer:
of means to multiple so it would equal 4 so the answer is false
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Formula
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![\text {Area of a kite = } \dfrac{pq}{2} \text { where p and q are the diagonals }](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20a%20kite%20%3D%20%7D%20%20%5Cdfrac%7Bpq%7D%7B2%7D%20%20%5Ctext%20%7B%20where%20p%20and%20q%20are%20the%20diagonals%20%7D%20)
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Find Area
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![\text {Area = } \dfrac{8 \times 22}{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20%3D%20%7D%20%20%5Cdfrac%7B8%20%5Ctimes%2022%7D%7B2%7D%20)
![\text {Area = } \dfrac{176}{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20%3D%20%7D%20%20%5Cdfrac%7B176%7D%7B2%7D%20)
![\text {Area = } 88 \ m^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20%3D%20%7D%2088%20%5C%20%20m%5E%7B2%7D%20)
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Answer: Area = 88m²-----------------------------
The number of pieces of 1/3 foot tall to make a 6 feet skyscraper is 18 pieces.
The model of a skyscraper comes in pieces and each piece is 1/3 feet tall.
After all the pieces are put together the skyscraper is 6 feet tall.
We have to calculate how many pieces were put together to make the 6 feet skyscraper.
Let X be the number of pieces put together to make a 6 feet skyscraper.
Now,
Each piece = 1/3 feet tall.
Since all the pieces together make 6 feet tall, we can write the number of pieces needed to make 6 feet tall as:
X x (1/3) = 6
X = 6 x 3 = 18
Thus, we need 18 pieces of 1/3 foot tall to make a 6 feet skyscraper.
Learn more about multiplication word problems here:
brainly.com/question/4686237
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