Answer:
approximation is often useful when it is not a very good one
Answer:
8.5
inches
Step-by-step explanation:
Scientific scientific notation is where the super small / super large number is multiplied by a 10 (E) to the power of a number. Here, the number is smaller than 8.5 so our power must be negative. As we are making it four "places" bigger, we use the exponent of -4.
Hope this helps, have a nice day! :D
Answer:
Option C is the correct answer.
Step-by-step explanation:
We are given,
<em>A graph where the function first increases and then decreases to touch the x-axis and the increases.</em>
It is required to find the corresponding situations.
So, from the options we have that,
The graph represents the speed of a vehicle which first increases (as it accelerates), then decreases (slows down) and then touch the x-axis (stops at the light) and then increases (accelerates on the ramp for a freeway).
Hence, option C is scenario that the graph describes.
Answer:
a) For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got: