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Viefleur [7K]
4 years ago
14

some friends need 100 bows for a project Sara brings 12 bows Angela brings 50 bows and Nora brings 34 bows how many more bows do

they need
Mathematics
2 answers:
Irina-Kira [14]4 years ago
7 0
They need 4 more because 12+50+34=96 96-100 is 4 hope this helps ya
elena-s [515]4 years ago
6 0
12+4+34=96 they need 4 more bows 96+4=100
hope this will help
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I need help with this question pls!
gladu [14]

Answer:

Answer is D

Step-by-step explanation:

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3 years ago
Can you help me with 5
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9514 1404 393

Answer:

  see below for the graph

Step-by-step explanation:

We can specify the location of the minimum and the axis of symmetry using the vertex form of the quadratic equation:

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We can put the given values into the equation to see what 'a' needs to be to make the function have the desired y-intercept.

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4 0
3 years ago
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ZanzabumX [31]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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The dimensions of the base of Box 2 are<br> by 4x - 1.<br> 4x² – x<br> 4x²_1<br> 4x4<br> 5x-1
Lisa [10]

Answer: 4x^2-x

Step-by-step explanation:

7 0
3 years ago
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Assume that the results of your class' statistics test are normally distributed. You know that you scored 1 standard deviation a
Gnom [1K]

Answer:

84%

Step-by-step explanation:

We have to remember that z-scores are values to find probabilities for any <em>normal distribution</em> using the <em>standard normal distribution</em>, a conversion of the normal distribution to find probabilities related to that distribution. One way to find the above z-scores is:

\\ z = \frac{x - \mu}{\sigma}

As a result, we can say that one standard deviation above the mean is equal to a z-score = 1, or that one standard deviation below the mean is equal to a z-score = -1, to take some examples.

The corresponding cumulative probability for a z-score = 1 (<em>one standard deviation above the mean</em>) can be obtained from the <em>cumulative standard normal table</em>, that is, the cumulative probabilities from z= -4 (four standard deviations below the mean) to the value corresponding to this z-score = 1.

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Applying this for the case in the question, the percentage of test scores below 69 (one standard deviation above the mean) is, thus, 84.134%, and rounding to the nearest whole number is simply 84%.

6 0
3 years ago
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