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2 years ago

I am in need of help :) please and thank you :):

Mathematics

2 answers:

nika2105 [10]2 years ago

8 0

It’s the second answer

Evgen [1.6K]2 years ago

5 0

Answer:

<h2>2nd Option:</h2><h2> $6 {x}^{2} + 43x + 55$ </h2>

Step-by-step explanation:

Given, 

Dimensions of the rectangular garden = 2x+11, 3x + 5

Therefore ,

Area of the rectangular garden

= (2x+11) × (3x + 5)

= 3x(2x + 11) + 5(2x + 11)

$= {6x}^{2} + 33x + 10x + 55$

$= 6 {x}^{2} + 43x + 55(ans)$

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nignag [31]

Answer:

A. 24.5

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Step-by-step explanation:

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43.8 - 36.7 = 7.1

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3 years ago

Is 0.7 greater or less than 9/10

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3 years ago

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Kamila [148]

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Step-by-step explanation:

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3 years ago

Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar

Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

$((a, b), (c, d))\in R$

Where $R$ is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

$\forall a \in A \Rightarrow (a,a) \in R$

Here we need to prove:

$\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R$

As per the given relation:

$((a,b), (a,b) ) \Rightarrow ab =ab$ which is true.

$\therefore$ R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

$\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R$

Here we need to prove:

$\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R$

As per the given relation:

$((a,b),(c,d)) \in R$ means $ad = bc$

$((c,d),(a,b)) \in R$ means $cb = da\ or\ ad =bc$

Hence true.

$\therefore$ R is symmetric.

3. R to be transitive, we need to prove:

$if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R$

$((a,b),(c,d)) \in R$ means $ad = cb$ .... (1)

$((c,d), (e,f)) \in R$ means $fc = ed$ ...... (2)

To prove:

To be $((a,b), (e,f)) \in R$ we need to prove: $fa = be$

Multiply (1) with (2):

$adcf = bcde\\\Rightarrow fa = be$

So, R is transitive as well.

Hence proved that R is an equivalence relation.

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3 years ago