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2 years ago

I am in need of help :) please and thank you :):

Mathematics

2 answers:

nika2105 [10]2 years ago

8 0

It’s the second answer

Evgen [1.6K]2 years ago

5 0

Answer:

<h2>2nd Option:</h2><h2> $6 {x}^{2} + 43x + 55$ </h2>

Step-by-step explanation:

Given, 

Dimensions of the rectangular garden = 2x+11, 3x + 5

Therefore ,

Area of the rectangular garden

= (2x+11) × (3x + 5)

= 3x(2x + 11) + 5(2x + 11)

$= {6x}^{2} + 33x + 10x + 55$

$= 6 {x}^{2} + 43x + 55(ans)$

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1 year ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

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This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

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$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

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$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

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3 years ago

Please help thank you very much

Tom [10]

Answer:

$4x^{2} -6x$

Step-by-step explanation:

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2 years ago

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Lelu [443]

Answer: it’s C

Step-by-step explanation:

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2 years ago