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nata0808 [166]
3 years ago
9

What is stands for BCPL explain ?​

Computers and Technology
1 answer:
krek1111 [17]3 years ago
8 0
Answer: Basic Combined Programming Language

Explanation: it is a procedural, imperative, and structured programming language, originally intended for writing compilers for other languages.
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The main benefit of the ordered list is that you can apply Binary Search( O( n log n) ) to search the elements. Instead of an unordered list, you need to go through the entire list to do the search( O(n) ).

The main cost of the ordered list is that every time you insert into a sorted list, you need to do comparisons to find where to place the element( O( n log n) ). But, every time you insert into an unsorted, you don't need to find where to place the element in the list ( O(1) ). Another cost for an ordered list is where you need to delete an element, you have an extra cost rearranging the list to maintain the order.

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File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
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Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

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    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

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