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vladimir1956 [14]
2 years ago
9

A box is shaped like a cube. The box has a length of 1 foot, a width of 1 foot, and aheight of 1 foot. What is the volume of the

box.​
Mathematics
2 answers:
andre [41]2 years ago
7 0

Answer:

The volume is 1

Step-by-step explanation:

To calculate volume, you just multiply width x length x height

iogann1982 [59]2 years ago
7 0

Answer:

1 cubic foot

Step-by-step explanation:

Volume= length times weight times height

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f f(x) and g(x) are inverse functions of each other, which of the following shows the graph of f(g(x))? On a coordinate plane, a
kvasek [131]

Answer:

5555.

Step-by-step explanation:

5555

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2 years ago
Calculator display for<br> 1/9
KIM [24]
1/9 on a calculator is 0.11111111
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2 years ago
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Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 m
dedylja [7]

Answer:

18.95%

Step-by-step explanation:

In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.

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9/20  

And the second event, with one less in each, would be:

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4 0
3 years ago
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25 10^6 in standard form
Alex

Answer:

0^6= 1000000. The final answer is 25000000.

6 0
3 years ago
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
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