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Yuki888 [10]
2 years ago
14

he section of paper shown in the pattern below is 1/4 of a circle. It will be wrapped around a cone. The wrapper will then be pa

inted.
Mathematics
1 answer:
uranmaximum [27]2 years ago
6 0

The volume of the cone based on the figure illustrated wil be 196cm³.

<h3>Host illustrate the information?</h3>

The information is incomplete and the complete question wast found online. An overview will be given.

Let's assume that the height is 4cm and the radius of the cone is 7cm. The volume of the cone will be:

= 1/3πr²h

= 1/3 × 3.14 × 7² × 4

= 196cm³

Learn more about cone on:

brainly.com/question/1082469

#SPJ1

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Police estimate that​ 25% of drivers drive without their seat belts. If they stop 6 drivers at​ random, find the probability tha
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17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

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In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so p = 0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.1780

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so, we can assume this is what the computers will cost in total because there seems to be no added tax or fees.


<em>i hope this helps, and have a great day! don't hesitate to ask if you need more help with this specific question! ♥ - eviezoom </em>


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The graph is Parabola or Graph of Quadratic Function.

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