The probability of one arrives within the next 10 minutes
when he already been waiting for one jour for a taxi is,
P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10)
= 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1
= 0.3679
The probability of one arrives within the next 10 minutes
when he already been waiting for one hour for a taxi is 0.3679
Answer:
Required probability equals 0.18%
Step-by-step explanation:
The probability that the primary and one auxiliary computer fails equals
1) Probability that A and B fails
2)Probability that A and C fails
Thus required probability equals

Answer:
tell your teacher to help u
Step-by-step explanation:
<span>What makes the statement true?</span>7^-2= 0.0204081633
Puede tomar una gota mejor para enter