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3 years ago

Is the given point interior, exterior, or on the circle (x + 2)2 + (y - 3)2 = 81?S(-2, 12)

Mathematics

2 answers:

Tasya [4]3 years ago

7 0

Answer:

S(-2, 12) lies on the circle

Step-by-step explanation:

Given : Equation of circle : $(x + 2)^2 + (y - 3)^2 = 81$

Point: S(-2, 12)

To Find: Is the given point interior, exterior, or on the circle

Solution :

After substituting the values,

If L.H.S of the given equation is less than R.H.S , So, the given point is interior.

If L.H.S of the given equation is greater than R.H.S , So, the given point is exterior.

If L.H.S =R.H.S , So, the given point is on the circle.

$(-2 + 2)^2 + (12 - 3)^2 = 81$

$(0)^2 + (9)^2 = 81$

$81 = 81$

Thus L.H.S =R.H.S

Hence the given point S(-2, 12) lies on the circle $(x + 2)^2 + (y - 3)^2 = 81$

Georgia [21]3 years ago

3 0

(x + 2)² + (y - 3)² = 81
x=-2, y=12

(-2 + 2)² + (12-3)² = 81
0² + 9² = 81
81 = 81

The given point S(-2, 12) is on the circle

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Help me ):

slavikrds [6]

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The same principles apply to the wall as it is also assumed to be rectangular.

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