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3 years ago

8

Factor completely. 16x^6-81=

1 answer:

uranmaximum [27]3 years ago

8 0

Answer:

(4x^3 - 9)(4x^3 + 9)

Step-by-step explanation:

16x^6 - 81

write this in the form of a^2 - b^2

(4x^3)^2 - (9)^2

since a^2 - b^2 = (a + b)(a - b) . Write,

(4x^3 - 9)(4x^3 + 9)

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What is the answer to (6+4)tothe3power-1tothe8power

Ipatiy [6.2K]

Hey there!

$\huge\boxed{(6 + 4)^3 - 1^8}$

$\huge\boxed{= 10^3 - 1^8}$

$\huge\boxed{10^3}$

$\huge\boxed{= 10\times10\times10}$

$\huge\boxed{= 100\times10 }$

$\huge\boxed{= 1,000}$

$\huge\boxed{1^{8}}$

$\huge\boxed{= 1\times1\times1 \times 1 \times 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1\times1}$

$\huge\boxed{= 1}$

$\huge\boxed{1,000 - 1}$

$\huge\boxed{= 999}$

$\huge\text{Answer: \textsf{999}}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\huge\boxed{\frak{Amphitrite1040:)}}$

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2 years ago

A parabola and it’s directrix are shown on the graph. What are the coordinates of the focus of the parabola?

Svetllana [295]

Answer:

a. (0,2)

Step-by-step explanation:

5 0

2 years ago

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8x = -6 please answer!!

Nikolay [14]

Answer:-3/4

Step-by-step explanation:

Get the x by itself by dividing both sides by 8 then reduce -6/8. When you reduce you get -3/4

4 0

3 years ago

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Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the

KonstantinChe [14]

Answer:

The center of the circle is

$(-\frac{3}{2},2)$

Step-by-step explanation:

Let the equation of the circle be

$x^2+y^2+2ax+2by+c=0$ , where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

$0^2+0^2+2a(0)+2b(0)+c=0$

$\implies c=0$

B(-3,0)

$(-3)^2+0^2+2a(-3)+2b(0)+c=0$

$\implies 9+0-6a+0+c=0$

$\implies -6a+c=-9$

But c=0

$\implies -6a=-9$

$\implies a=\frac{3}{2}$

C(1,2)

$1^2+2^2+2a(1)+2b(2)+c=0$

$1+4+2a+4b+c=0$

$2a+4b+c=-5$

Put the value of 'a' and 'c' to find 'b'

$2(\frac{3}{2})+4b+0=-5$

$3+4b+0=-5$

$4b=-5-3$

$4b=-8$

b=-2

Hence the center of the circle is

$(-\frac{3}{2},2)$

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3 years ago

Which of the following situations have a net sum of 0? Select three that apply.

statuscvo [17]

Answer:

B,C,E

Step-by-step explanation:

Done this before. A is the first and so on and so forth

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2 years ago

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