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3 years ago

Factor completely. 16x^6-81=

Mathematics

1 answer:

uranmaximum [27]3 years ago

8 0

Answer:

(4x^3 - 9)(4x^3 + 9)

Step-by-step explanation:

16x^6 - 81

write this in the form of a^2 - b^2

(4x^3)^2 - (9)^2

since a^2 - b^2 = (a + b)(a - b) . Write,

(4x^3 - 9)(4x^3 + 9)

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Given

kolbaska11 [484]

Answer:

∠CBD = 125°

Step-by-step explanation:

The angle sum theorem tells you that ...

∠ABC +∠CBD = ∠ABD

8x -41° +9x +17° = 180° . . . . . . a "straight angle" has a measure of 180°

17x -24° = 180° . . . simpify

17x = 204° . . . . . . add 24°

x = 12° . . . . . . . . . . divide by 17

Now the measures of the angles can be found from their expressions.

∠ABC = 8(12) -41° = 55°

∠CBD = 9(12) +17° = 125°

4 0

3 years ago

How Many texts?please help.

kirza4 [7]

Answer:

176

Step-by-step explanation:

91/9.10=0.10

17.60/0.10=176

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2 years ago

Read 2 more answers

Find the polynomial of minimum degree, with real coefficients, zeros at x=4+4i and x=2, and y-intercept at 64

Mice21 [21]

Answer:

$\displaystyle -x^3+10x^2-48x+64$

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

$x= 4+4i\text{ and } x = 2$

As well as a y-intercept of 64.

By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

$P(x)=a(x-p)(x-q)...$

Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.

Substitute:

$P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))$

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

$\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}$

Hence:

$P(x)=a(x-2)(x^2-8x+32)$

Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:

$64=a(0-2)(0^2-8(0)+32)$

Solve for a:

$-64a=64\Rightarrow a=-1$

Our factored polynomial is:

$P(x)=-(x-2)(x^2-8x+32)$

Finally, expand:

$\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}$

8 0

3 years ago

Use a coterminal angle to find the exact value of the expression. Do not use a calculator.

melamori03 [73]

c.
d.Seleccione una respuesta.

5 0

3 years ago

Find the sine of Write your answer in simplified, rationalized form. Do not round. Please help!!!!!

erma4kov [3.2K]

Answer:

Sin (E) = √74/(2√23)

Step-by-step explanation:

Reference Angle = E

Hypotenuse = 2√23

Adjacent = 3√2

Opposite = DC = √(2√23)² - (3√2)²) = √(4*23 - 9*2) = √(92 - 18) = √74 (pythagorean theorem)

Recall SOHCAHTOA.

Thus,

Sin (E) = opp/hyp

Sin (E) = √74/(2√23)

6 0

2 years ago