Answer:
- 3*2=

Step-by-step explanation:
<u>Given</u><u> </u><u>that</u><u>,</u><u> </u>
x*y=
<h3>
<u>SO</u><u>,</u><u> </u></h3>
3*2=

<u>Therefore</u><u>:</u><u>-</u>

Answer:
it would be the second answer because the shape has to get 3/4 smaller than the pre-image
Step-by-step explanation:
The concept of historical cost in accounting involves valuing business resources at their purchase price. This is further explained below.
<h3>What is the historical cost?</h3>
Generally, historical cost is a value of measure used in accounting that records the value of an asset on the balance sheet at its original cost when purchased by the firm.
In conclusion, valuing business resources at their purchase price is what historical cost is about.
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Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3.
<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>
<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>
<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
<span>==> x/6 = (3√3 - h)/(3√3) </span>
<span>==> x = (6√3 - 2h)/√3 </span>
<span>Thus, the area of the upper triangle is: </span>
<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>
<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>
<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>
<span>Solving with the Quadratic Formula gives: </span>
<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>
<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>
<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>
<span>I hope this helps! ^^ Brainliest Please?</span><span>
</span>
Answer:

Step-by-step explanation:
From the graph,
The initial red incline is a straight line passing through the origin.
So, a straight line passing through the origin is of the form:

Where, 'm' is the slope.
Now, the slope of a given as the change in y value to change in x value.
Consider the two end points of the red line (0, 0) and (4, 6).
The slope with two points
on the line is given as:

Plug in
. Therefore, slope is:

Hence, the equation of the initial red incline is:
