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Natali5045456 [20]
3 years ago
15

A study is undertaken to find out how much water, in gallons, is in Lake Michigan. Which type of data will the study analyze?

Mathematics
1 answer:
Drupady [299]3 years ago
8 0
<span>A.
continuous data
gallons in a lake would be continuous data because it is not counted in integers but measured by how much volume is in the lake. 
</span>
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One of the quarterbacks last weeks completed 24 out of 30 passes. If he continues that trend this week and he throws the ball 40
SOVA2 [1]
30/40 passes :)
explanation: 24/30=75%
75% of 40=30
4 0
3 years ago
What is the measure of arc bc
aleksklad [387]

Answer:

100 deg

Step-by-step explanation:

As the property of inscribed angle on circle, angle BEC = (1/2)(arc BC)

=> arc BC = 2 x angle BEC = 2 x 50 = 100 deg

3 0
3 years ago
If f(x) = x and g(x) = 2, what is (fºg)(x)?
ICE Princess25 [194]

Step-by-step explanation:

(fog)(x) = f[g(x)]

f(g(x))

f(x-2)

since f(x) = 1 / x

answer: 1/x-2

1/x-2 looks like 1/x but the asymptotes(dips in the graphs) will be at x = 2 since is undefined

8 0
3 years ago
Solve <br>60000000+63636733-7373 ​
Yuri [45]

Answer:

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Step-by-step explanation:

60000000+63636733-7373 =123629360

i hope this helped

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7 0
3 years ago
If √3 = 1.732, then √[(√3-1)/(√3+1)] is equal to​
adelina 88 [10]

Step-by-step explanation:

<h3><u>Given Question :-</u></h3>

\sf \:  \sqrt{3} = 1.732, \: then \:  \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} }

\red{\large\underline{\sf{Solution-}}}

Given expression is

\rm :\longmapsto\: \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} }

<em>On rationalizing the denominator, we get </em>

\rm \:  =  \:  \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1}  \times \dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  - 1} }

\rm \:  =  \:  \sqrt{\dfrac{ {( \sqrt{3}  - 1)}^{2} }{( \sqrt{3}  + 1)( \sqrt{3}  - 1)} }

<em>We know, </em>

\boxed{ \tt \: (x - y)(x + y) =  {x}^{2} -  {y}^{2} \: }

<em>So, using this, we get </em>

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{ {( \sqrt{3})}^{2}  -  {(1)}^{2} } }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{ 3 - 1} }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{2} }

\rm \:  =  \: \dfrac{ \sqrt{3}  - 1}{ \sqrt{2} } \times \dfrac{ \sqrt{2} }{ \sqrt{2} }

\rm \:  =  \: \dfrac{(1.732 - 1) \sqrt{2} }{2}

\rm \:  =  \: \dfrac{0.732 \times \sqrt{2} }{2}

\rm \:  =  \: 0.366 \sqrt{2}

Hence,

\rm :\longmapsto\: \boxed{ \rm{ \: \:  \:   \sqrt{\dfrac{ \sqrt{3}  - 1}{ \sqrt{3}  + 1} } = 0.366 \sqrt{2} \:  \:  \: }}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>More Identities to know :- </h2>

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)² = (a - b)² + 4ab

(a - b)² = (a + b)² - 4ab

(a + b)² + (a - b)² = 2(a² + b²)

(a + b)³ = a³ + b³ + 3ab(a + b)

(a - b)³ = a³ - b³ - 3ab(a - b)

3 0
3 years ago
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