All categories

3 years ago

How can you prove: secθ = cscθtanθ

1 answer:

3 0

$\sec \theta=\csc \theta\tan \theta\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\sin \theta}\cdot\dfrac{\sin \theta}{\cos \theta}\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\cos \theta}$

You might be interested in

A high school basketball player attempted 42 free throws in a season. An analyst determined that the player successfully made 5

patriot [66]

The answer is 35 free throws

5 0

4 years ago

Read 2 more answers

Evaluate 9 ÷ 3[(18 − 6) − 22]. 0.188 0.375 24 48

Natasha2012 [34]

Answer:

Step-by-step explanation:

0.375

6 0

3 years ago

Read 2 more answers

Find the area of the following shape. Show work.

Serga [27]

Answer:

The total area:

12 units²

Step-by-step explanation:

There are three parts on this shape:

1 big right triangle

1 rectangle

1 small right triangle

Big right triangle:

area = (4*4)/2 = 16/2 = 8units²

Rectangle:

area = 2*1 = 2units²

Small right triangle:

area = (2*2)/2 = 2units²

Total area

8+2+2 = 12 units²

6 0

3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :