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krok68 [10]
3 years ago
12

PLEASE HELP!!!!!!!!!

Business
1 answer:
VladimirAG [237]3 years ago
7 0

Answer:

housing- $554

food- $245

healthcare- $500

pensions- $350

entertainment- $118

transportation- $247

cash- $155

other- $94

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Airline Accessories has the following current assets: cash, $112 million; receivables, $104 million; inventory, $192 million; an
ioda

Answer:

Current Ratio = 2.67

Acid-Test Ratio = 1.50

Explanation:

Given:

Current assets:

cash = $112 million

receivables = $104 million

inventory = $192 million

other current assets = $28 million

Liabilities:

accounts payable = $118 million

current portion of long-term debt = $45 million

Long-term debt = $33 million

FInd:

Current ratio

Acid-test ratio

Computation:

Current assets = Cash + Receivables + Inventory + Other Current Assets

Current assets = [112 + 104 + 192 + 28] Million

Current assets = $436 million

Current Liabilities = Accounts Payable + Current portion of Long term debt

Current Liabilities = [118 + 45] million

Current Liabilities = $163 million  

Current Ratio = Current assets / Current Liabilities

Current Ratio =  $436 Million / $163 Million

Current Ratio = 2.67  

Acid-Test Ratio = [Current Assets – Inventories] / Current Liabilities

Acid-Test Ratio = [$436 Million - $192 Million] / $163 Million  

Acid-Test Ratio = $244 Million / $163 Million

Acid-Test Ratio = 1.50  

4 0
3 years ago
For 1-year SPX options, we observe that the 25-delta put implied volatility is at 45%, the 50-delta call implied volatility is a
Lerok [7]

Answer:

Option B, positively skewed, is the right answer.

Explanation:

A positive-skewed distribution generally has a long right or positive tail. The positive-skew distributions are also known as the Right-skewed distribution. The main reason behind calling this a positive-skew is that this skew has a long tail in the positive direction on the number line.

In the given question, positively-skewed implies to one-year return risk-neutral distribution, as the delta put raises, the volatility decreases but not in the same proportion. In such a condition, the median will be less than the mean. Therefore, it will be Right-Skewed or Positively Skewed Distribution.

8 0
3 years ago
Candice’s first job was at the grocery store making deli food. While in culinary school, she worked part time in a restaurant ki
Papessa [141]
Move up the career ladder
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4 years ago
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What does a Human Resources manager do
Sveta_85 [38]

Hello There!

A human resource manager is a person within a business/company or possibly an other organization and they handle and supervise personnel matters. These could include hiring, training and even firing.

7 0
3 years ago
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Sonbull [250]

Answer:

Mean = 47

Median = 47.38

Standard Deviation = 12.73

Explanation:

Note: You wrote " 40 manufacturing companies, but the total number of companies you actually listed is 75, definitely you meant 75.

Let y represent the range of advertising expenditure, f represent the number of companies, x represent the midpoint of the range of advertising expenditure.

y                                       f                      x                  fx                    fx²

$20 to under $30            9                     25               225               5625

$30 to under $40            13                    35               455               15925

$40 to under $50            21                    45               945              42525

$50 to under $60            18                    55               990              54450

$60 to under $70            14                     65               910               59150

                                       n = 75                           \sum fx = 3525      

\sum fx^2 = 177675

Mean, \bar{X} = \frac{\sum fx}{n}

\bar{X} = \frac{3525}{75} \\\bar{X} = 47

Standard Deviation:

SD = \sqrt{\frac{n \sum fx^2 - (\sum fx)^2}{n(n-1)} } \\SD = \sqrt{\frac{(75*177675) - (3525)^2}{75(75-1)} }\\SD = 12.73

Median:

Get the cumulative frequencies(cf)

         y                                        f                                cf

$20 to under $30                     9                                9

$30 to under $40                     13                               22

$40 to under $50                     21                               43

$50 to under $60                     18                               61

$60 to under $70                      14                              75

                                                N = 75

Median = Size of (N/2)th item

Median = Size of (75/2)th item

Median = Size of (37.5)th item

The median class = 40 to under 50

Lower limit, L₁ = 40

Cumulative frequency, cf = 22

f = 21

Class Width, h = 10

Median = L_1 + \frac{ (N/2) - cf}{f} * h\\

Median = 40 + \frac{ (75/2) - 22}{21} * 10\\

Median = 47.38

8 0
4 years ago
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