You answer 24 questions on a 100 point test correctly and earn 96%.

14 kg of apples cost $154.how much would 16kg cost

ankoles [38]

We can set up a proportion, and let x be the amount 16kg would cost: 14/154=16/x. We simplify 14/154 = 1/11. Next, we cross-multiply to get (1)(x)=(16)(11), so x=176. Therefore, 16kg of apples cost $176.
---
Hope this helps!

4 0

2 years ago

Read 2 more answers

What is the approximate circumference of the circle shown below?

Serggg [28]

Hey, there’s no circle for me to look at unfortunately!

4 0

3 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

2 years ago

When the movie is half over, popcorn sells for half price. Full price popcorn is $3.50, and drinks are $1.35. Determine the cost

Nady [450]

Full price of popcorn: $3.50
Price of popcorn after half the movie: $1.75
price of drinks: $1.35

The question is....."Determine the cost for purchasing 3 orders of popcorn and 3 drinks when the movie is half over."

$1.75*3=$5.25
$1.35*3=$4.05

the price of the 3 orders of popcorn would be $5.25
The price of the 3 orders of drink would be $4.05

5.25 + 4.05 = $9.30

In total the 3 orders of popcorn and 3 orders of drink would cost $9.30

Hope this helps! :)

3 0

2 years ago

Read 2 more answers

Can someone help me find x.

Harman [31]

Answer:

Step-by-step explanation:

6x+9=63

6x=63-9

6x=54

x=54/6

x=9

I encourage you to figure out the justification yourself.

8 0

3 years ago