Answer:
Required series is:
Step-by-step explanation:
Given that
---(1)
We know that:
---(2)
Comparing (1) and (2)
---- (3)
Using power series expansion for 
![=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]](https://tex.z-dn.net/?f=%3D-%5Bc%2B%5Csum%5Climits%5E%7B%20%5Cinfty%7D_%7Bn%3D0%7D%20%28-1%29%5E%7Bn%7D%5Cfrac%7Bx%5E%7B2n%2B1%7D%7D%7B2n%2B1%7D%5D)
as
Hence,
i cant describe but i put y=1/x+3 -4 on the graph hope this helps
For this case we have the following vector:
v = (- 8, 2)
Using product point we have:
v.v = (-8, 2). (- 8, 2)
v ^ 2 = (-8) * (- 8) + (2) * (2)
v ^ 2 = 64 + 4
v ^ 2 = 68
v = root (68)
v = root (4 * 17)
v = 2 * root (17)
Answer:
v = 2 * root (17)
option c
-30 is the answer
-6+4(-6)
-6+(-24)
-30
The pythagorean theorem equation is a^2 (a squared) + b^2 (b squared) = c^2 (c squared)
so a^2+b^2=c^2
