ASAP Solve 1/9 (3/5) - 1/5 (7/3)=?

For most people the ratio of the length of their head to their total height is 1:7 use proportions to test your measurements and

alexandr1967 [171]

The correct answer for this question is this one: 5 / 7

There exists the same question from other source that has the continuation of the problem. Use proportions to test your measurements and see if they match this ratio. Height is 5ft

So this how to solve this:

Set the equation as:
7x = 5
x = 5 / 7

7 0

2 years ago

What are the terms in the expression 6ab +7c-8d +11f

Alisiya [41]

The terms are a b c d andf

7 0

3 years ago

Is this expression equivalent to 1.5? 0.15 / 10 (0.15 divided by 10)

dimulka [17.4K]

Answer:

False

Step-by-step explanation:

0.15/10 equals 0.015

6 0

2 years ago

Your savings account pays 1.75% interest per year. You make a $500 deposit. How much interest does the account earn in the first

GaryK [48]

1,75% = 0,0175

per month: 0,0175/12 = 0,00145833

500*0,00145833 = 0,73$ interest

8 0

3 years ago

Read 2 more answers

A random sample of 144 recent donations at a certain blood bank reveals that 81 were type A blood. Does this suggest that the ac

Reptile [31]

Answer:

Null hypothesis: $p=0.4$

Alternative hypothesis: $p \neq 0.4$

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

Step-by-step explanation:

Information given

n=144 represent the random sample taken

X=81 represent the number of people with type A blood

$\hat p=\frac{81}{144}=0.5625$ estimated proportion of people with type A blood

$p_o=0.4$ is the value that we want to verify

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4$

Alternative hypothesis: $p \neq 0.4$

the statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98$

Now we can calculate the p value with this probability taking in count the alternative hypothesis:

$p_v =2*P(z>3.98)=0.0000689$

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

3 0

3 years ago