$\sec \theta=\csc \theta\tan \theta\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\sin \theta}\cdot\dfrac{\sin \theta}{\cos \theta}\\\\ \dfrac{1}{\cos \theta}=\dfrac{1}{\cos \theta}$

3 0

3 years ago

Which expression represents the area of the shaded sector

11111nata11111 [884]

the answer should be C.

4 0

3 years ago

Consider the figure below. Abraham cut regular pentagon ABCDE into quadrilateral BEGC. Which of the following statements is true

Genrish500 [490]

Let 'n' be the number of side of a regular polygon each angle are equal and sum of each angle equal to (n-2)×180. $\\$ ∴For a regular pentagon have five equal side, n=5 $\\$ ∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108° $\\$ Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio $\\$ Therefore ∠ABE : ∠CBE = 36: 72 $\\$ ∴ ∠GCB + ∠CBE = 108° +72°=180°

5 0

3 years ago

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