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3 years ago

Pls help im not smart enough ;-;

Mathematics

1 answer:

evablogger [386]3 years ago

7 0

PART1:

First Combination:
Pizza ($7) + Chicken Strips ($6) + Biscuits ($3) + Grapes ($4) = $20

Second Combination:
Dog Food ($13) + Bread ($3) + Crackers ($2) + Broccoli ($2) = $20

Third Combination:
Shampoo ($4) + Tissues ($3) + Pizza ($7) + Eggs ($3) + Biscuits ($3) = $20

PART 2:

First Combination:
$7.20 + $5.70 + $2.90 + $3.70 = $19.60
No, I wouldn’t have gone over the limit

Second Combination:
$13.40 + $3.50 + $2.00 + $1.90 = $20.80
Yes, I would have gone over the limit

Third Combination:
$3.50 + $2.60 + $7.20 + $2.50 + $2.90 = $18.70
No, I wouldn’t have gone over the limit

Hope this helps!!

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1. Given the equation (x – 3)2 – 32 = 17 a)

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We know that

The square root property is one method that is used to find the solutions to a quadratic equation. This method involves taking the square roots of both sides of the equation.
(x – 3)² – 32 = 17-------> (x – 3)² = 17+32-----------> (x – 3)² = 49
(x – 3)² = 7²--------> will take the square root of each side
so
√(x – 3)²=(+-)√7²------> notice the use of the sign (+-), this will give us both a positive and a negative root

then

x-3=7--------> x=10
x-3=-7-------> x=-4

the answer Part a) is
x=10
x=-4

Part b) Explain why the given equation has two solutions.

the answer part b) is
Because exist the possibility of two roots for every square root, one positive and one negative

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3 years ago

Harold bought 2 pairs of sandals for the same price. He also bought a pair of socks for $3. How much did one pair of sandals cos

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3 years ago

In a survey of adults aged 57 through 85 years, it was found that 86.6% of them used at least one prescription medication. Com

OleMash [197]

Answer:

a) 272 used at least one prescription medication.

b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

Step-by-step explanation:

Question a:

86.6% out of 3149, so:

0.866*3149 = 2727.

272 used at least one prescription medication.

Question b:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 3149, \pi = 0.866$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876$

For the percentage:

0.856*100% = 85.6%

0.876*100% = 87.6%.

The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).

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