Answer:
11∗2+13∗4+15∗6+⋯+199∗100=?
=(1−12)+(13−14)+(15−16)+⋯+(199−1100)
=(1+13+15+17+⋯+199)−(12+14+16+⋯+1100)
=(1+13+15+17+⋯+199)−12(1+12+13+⋯+150)
=∑k=15012k−1−∑k=15012k
Continue further.
Answer:
5.00 is the value of the initial balance (i.e. when time is 0) in the savings account.
Step-by-step explanation:
We have the function, 
which represents the balance in the savings account.
Now, if we substitute x= 0, we have,
implies 
As, 'any number with power 0 is equal to 1 i.e. 
'.
We get,
implies 
i.e. f(0)= 5.00
Thus, we see that,
5.00 is the value of the initial balance (i.e. when time is 0) in the savings account.
Answer:
There were 12 + 28 = 40 pieces of fruit in the basket.
Step-by-step explanation:
Suppose there were x oranges and y grapefruit.
Then we have
1 /3 x = 4
x = 4*3 = 12.
1/4 y = 7
y = 7*4 = 28.
Answer:the second one
Step-by-step explanation:
y1= log 3 etc so it the second one
Answer:
Step-by-step explanation:
First move the numbers from the Left hand side to the right hand side. To do so, as it is an equation i.e. both sides must remain the same, you add or subtract the same numbers on both side.
5 + 13k - 61 = 17
5 - 5 + 13k - 61 + 61 = 17 - 5 + 61
13k = 73
k = 73 / 13
k = 5.62 (approximately)
