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Elza [17]
3 years ago
12

Who ever helps me on this and is correct will be marked brainlist !​

Mathematics
1 answer:
dangina [55]3 years ago
3 0

Answer:

y=3x^2 - 4

Step-by-step explanation:

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A bar graph is the best graph to use

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A total of 20% of a fire department's firefighters are in the Special Units Division. A total of 8% of the department's firefigh
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Find the distance (8,-7) (-4,-2)
Vinil7 [7]

Distance = 13 units

Point A: (8, -7)

Point B: (-4, -2)

\sqrt{(8 + 4)^{2} + (-7 + 2)^{2} }

\sqrt{(12)^{2} + (-5)^{2} }

\sqrt{144 + 25 }

\sqrt{169}

13

7 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST CAR!!!! HELP
Digiron [165]

Answer:

111°

Step-by-step explanation:

Let the centre of the circle be C

mRQ=157 (marked)

The angle at the centre of a circle standing on an arc is twice any angle at the circumference, standing on the same arc. So <SCR=2(SQR)=2(46)=92. mSR=<SCR=92

All the arc measure add up to 360 so:

mSQ+mRQ+mSR=360

mSQ+157+92=360

mSQ=360-249=111

4 0
3 years ago
Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
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