The urethra is the tube that conducts the flow of urine in both sexes from the interior of the body to the external world. In males, semen also travels through the urethra during sexual intercourse. The urethra connects the bladder, the collection site for urine to the outside world. In males, the urethra is 8 inches long, while in females, the urethra is only 2 inches long. So the primary difference is one of length. Another difference would be the path the urine takes getting from the bladder to the external world. In females, the path is more direct, while in males, the path is more curving. This curved path makes catheterization of males more difficult than females. Due to the short length of the urethra in females, infection can be a problem. Urethritis is an inflammation of the urethra common in females. The passing of kidney stones is another affliction that strikes both sexes in the area of the urethra.
Black fur in mice (B) is dominant to brown fur (b). Short tails (T) are dominant to long tails (t). (C) 1 / 2 of the progeny of crosses Bb Tt × BB tt will be expected to have black fur and long tails.
Crosses among individuals differing in two traits is known as a dihybrid cross.
Mice with genotype Bb Tt will form 4 types of gametes, namely, BT, Bt, bT and bt, while those containing the genotype BB tt will produce gametes with 'Bt' combination.
On crossing Bb Tt × BB tt, we will get 16 possible genotypes. However, only 8 offspring will have black fur (B) and long tails (t) with the possible genotypes- BBtt and Bbtt.
Thus, on dividing 8 by 16 we get 1/2.
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Answer:
Nonhuman life in an urban ecosystem differs from that in an undeveloped forest ecosystem
Explanation:
(1) All the genotypes are as follows: AABB, AaBB, AABb, AaBb, aaBB, aaBb, AAbb, Aabb, aabb.
(2) Assuming that Aa is dominant and Bb is recessive, there will be 9 phenotypes with both A and B allele dominant (i.e. AaBb, AABb); there will be 3 phenotypes with just the A allele dominant (i.e. Aabb, AAbb); there will be 3 phenotypes with just the B allele dominant (i.e. aaBb, aaBB); and there will be 1 phenotype with both alleles recessive (i.e. aabb). The phenotypic ratio in this case is 9:3:3:1.
(3) The probability of producing an offspring with the aabb genotype is 1/16 or 6%.
